Put ammonia, phenylamine and propanamine in order of base strength. Explain your answer.
CH3CH2CH2NH2 > NH3 > C6H6NH2
CH3CH2CH2NH2 - alkyl induction pushes electron density onto Nitrogen lone pair, more available to accept proton
NH3 - N lone pair available to accept proton but no increase in electron density
C6H6NH2 - N lone pair delocalised into benzene ring therefore less available to accept proton