MYELINATED AXON

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Created by
Jasmine Singh

Cards (1)

  • PASSAGE OF ACTION POTENTIAL ALONG UNMYELINATED AXON?
    1. Resting potential (overall concentration of positive ions) is greater outside axon than inside
    2. Axon membrane is polarised
    3. Stimulus causes influx of Na+ = reversal of charge (action potential) on axon membrane
    4. Axon membrane is depolarised
    5. VGNa+C along axon open
    6. Resulting influx of Na+ in this region = depolarisation
    7. Behind new region of depolarisation VGNa+C close and VGK+C open
    8. Outward movement of K+ = repolarisation of area behind action potential
    9. Repolarisation of axon returns it to resting potential until new stimulus occurs