Computing

Cards (9)

  • How the virtual memory works? Programs/data not currently in use are transferred to the hard disk, Programs/data are moved from virtual memory into RAM as they are needed. Enables more programs to run than installed physical memory will allow, ldeal for multitasking systems
  • The RAM is the computers main memory where it temporary stores instructions and data in use by the CPU.
    The purpose of a ROM is to provide the initial instructions when the computer is first powered on. Difference between ROM and RAM:
    ROM is read only. RAM is read/write.
    ROM is non-volatile
    RAM is volatile.
    ROM is small.
    RAM is comparatively larger.
  • Purpose of secondary storage is to store the operating systems, applications and data when the computer is turned off.
    Below are characteristics that need to be considered when selecting secondary storage: Capacity Speed Portability Durability Reliability Cost Some RAM may be needed in a game to store the progress of the game as its being played.
  • Primary storage is used to store instructions and data while the computer is running. Primary storage is physically located much closer to the processor, as well as having much faster read/write times than secondary storage. A cartridge for a portable games console could be ROM be because the instructions of the games does not need to be changed. The virtual memory is a section created temporarily in the main memory (RAM). This is needed when the computer is running a lot of programs/instructions at once and the RAM is running low,
  • What is the conversion factor from megabytes to gigabytes?
    1 mb = 0.001 gb
  • How do you calculate the storage requirement in gigabytes for a given scenario?
    By converting megabytes to gigabytes using the conversion factor.
  • If you have 0.1 mb and need to find the storage requirement for 3 units, what is the calculation?
    0.1 * 3 = 0.3 mb
  • How do you convert 0.3 mb to gigabytes?
    0.3 * \frac{120}{1000} = 0.036 gb
  • What is the final storage requirement in gigabytes for the given scenario?
    0.036 gb