Chinese

Cards (42)

  • What is the Chinese word for "to cook"?
    做饭 (zuò fàn)
  • What is the Chinese word for "newspaper"?
    报纸 (bào zhǐ)
  • What is the Chinese word for "advertisement"?
    广告 (guǎng gào)
  • What is the Chinese word for "vicinity"?

    附近 ( jìn)
  • What is the measure word for a suit or set in Chinese?

    (tào)
  • What is the Chinese word for "apartment"?
    公寓 (gōng yù)
  • What does "出租" (chū zū) mean in English?

    To rent out
  • What is the Chinese word for "to walk"?
    走路 (zǒu lù)
  • What is the Chinese word for "bedroom"?

    卧室 (wò shì)
  • What is the Chinese word for "minute"?
    分钟 (fēn zhōng)
  • What are the Chinese words for "to cook," "newspaper," and "advertisement"?
    • To cook: 做饭 (zuò fàn)
    • Newspaper: 报纸 (bào zhǐ)
    • Advertisement: 广告 (guǎng gào)
  • What are the Chinese words for "vicinity," "apartment," and "bedroom"?

    • Vicinity: 附近 (fù jìn)
    • Apartment: 公寓 (gōng yù)
    • Bedroom: 卧室 (wò shì)
  • What are the Chinese words for "to rent out," "to walk," and "minute"?
    • To rent out: 出租 (chū zū)
    • To walk: 走路 (zǒu lù)
    • Minute: 分钟 (fēn zhōng)
  • What is the first step in solving the problems in the worksheet?
    Identify and write down the givens and the unknown.
  • Why is it important to show all work for each problem?
    To demonstrate the equation used, substitution with units, and the final answer with units.
  • What is the equation used to find the distance traveled during acceleration?
    • Use the equation:
    d=d =vit+ v_i t +12at2 \frac{1}{2} a t^2
    • Where:
    • \(d\) = distance
    • \(v_i\) = initial velocity
    • \(a\) = acceleration
    • \(t\) = time
  • How far does Mr. Crawford travel during his acceleration from 71 m/s to 420 m/s at 28 m/s²?
    Use the equation: d=d =(vf2vi2)2a= \frac{(v_f^2 - v_i^2)}{2a} =(4202712)2×28 \frac{(420^2 - 71^2)}{2 \times 28}
  • What is the mass of the ATV mentioned in the second problem?
    120 kg
  • What is the initial condition of the ATV in the second problem?
    The ATV is initially at rest.
  • How much time does it take for the ATV to accelerate uniformly for a distance of 53 meters at 4.1 m/s²?
    Use the equation: d=d =vit+ v_i t +12at2 \frac{1}{2} a t^2 to solve for \(t\).
  • What is Superman's initial speed in the third problem?
    32 m/s
  • What is the deceleration rate of Superman in the third problem?
    • 2.7 m/s²
  • How far does Superman travel while decelerating over a distance of 120 meters?
    Use the equation: vf2=v_f^2 =vi2+ v_i^2 +2ad 2a d to find \(v_f\).
  • What is King Kong's initial speed in the fourth problem?
    29 m/s
  • What is the acceleration rate of King Kong in the fourth problem?
    1. 0 m/s²
  • How do you calculate King Kong's final speed after accelerating for 4.8 seconds?
    Use the equation: vf=v_f =vi+ v_i +at at
  • What is the speed of light in a vacuum needed for problem 5?
    It is a constant value found in the Physics Reference Tables.
  • How do you find the time it takes light to travel from Earth to the Moon?
    Use the equation: t=t =dv \frac{d}{v}
  • How far will sound travel in air at STP in 0.91 ms?
    Convert 0.91 ms to seconds and use the equation: d=d =vt vt
  • What is the speed of sound in air at STP?
    It is a constant value found in the Physics Reference Tables.
  • How do you calculate the acceleration of the UFO in problem 8?
    Use the equation: a=a =d12t2 \frac{d}{\frac{1}{2} t^2} where \(d = 98\) m and \(t = 3.9\) s.
  • What is Spiderman's deceleration rate in problem 9?
    • 12 m/s²
  • How do you find Spiderman's initial speed while decelerating over a distance of 1.5 meters?
    Use the equation: vf2=v_f^2 =vi2+ v_i^2 +2ad 2a d to solve for \(v_i\).
  • What is Chuck Norris's initial speed in problem 10?
    25 m/s
  • What is the acceleration rate of Chuck Norris in problem 10?
    18 m/s²
  • How do you calculate the distance Chuck Norris travels in 6.0 seconds?
    Use the equation: d=d =vit+ v_i t +12at2 \frac{1}{2} a t^2
  • What is Queen Amidala's initial speed in problem 11?
    167 m/s
  • What is the time taken by Queen Amidala to come to rest?
    1. 5 seconds
  • How do you calculate Queen Amidala's acceleration while coming to rest?
    Use the equation: a=a =vfvit \frac{v_f - v_i}{t}
  • What are the steps to solve the problems in the worksheet?
    1. Identify givens and unknowns.
    2. Find the appropriate equation from the Reference Tables.
    3. Show all work:
    • Equation used
    • Substitution with units
    • Final answer with units