RC and RL Time Constants

Cards (21)

  • transient voltage
    response of capacitors and inductors to sudden changes in DC voltage; unlike resistors (respond instantaneously to applied voltage), capacitors and inductors react over time as they absorb and release energy
  • Since capacitors store energy in the form of an electric field, they tend to act like small secondary-cell batteries, being able to store and release electrical energy
  • fully discharged
    maintains zero volts across its terminals
  • charged
    maintains a steady quantity of voltage across its terminals, just like a battery
  • When capacitors are placed in a circuit with other sources of voltage, they will absorb energy from those sources, just as a secondary-cell battery will become charged as a result of being connected to a generator
  • A full discharged capacitor, having a terminal voltage of zero, will initially act as a short-circuit when attached to a source of voltage, drawing maximum current as it begins to build a charge
    • the terminal voltage rises to meet applied voltage from the source, and the current through the capacitor decreases
    • once capacitor has reached full voltage of source, it stops drawing current from it, and behave as an open-circuit
  • asymptotic
    approach final values, getting closer and closer over time, but never exactly reach their destinations
  • While capacitors store energy in an electric field (produced by voltage between two plates), inductors store energy in a magnetic field (produced by current through wire)
  • Stored energy in an inductor tries to maintain a constant current through its windings. Inductors oppose changes in current
  • fully discharged inductor (no magnetic field)

    zero current through it; initially acts as an open-circuit when attached to a source of voltage (as it tries to maintain zero current), dropping max voltage across its leads
    • over time, inductor's current rises to max value allowed by circuit, and terminal voltage decreases to a minimum (current stays at max level and behaves as short circuit)
  • Steps to calculate any values in a reactive DC circuit over time:
    1. identify starting and final values for whatever quantity the capacity or inductor opposes change in (capacitors = voltage, inductors = current)
    2. Calculate the time constant of the circuit (series RC: tau = RC, series L/R: tau = L/R)
  • time constant
    the amount of time it takes for voltage or current values to change approximately 63% from their starting values to their final values in a transient situation
  • Universal Time Constant Formula
    change = (final - start)(1 - 1/e^[t/tau])
    final = value of calculated variable after infinite time (ultimate value)
    start = initial value of calculated variable
    e = Euler's number
    t = time in seconds
    tau = time constant for circuit in seconds
  • discharge
    when energy is being released from the capacitor or inductor to be dissipated in the form of heat by a resistor
  • When discharging, heat dissipated by the resistor constitutes energy leaving the circuit, and as a consequence, the reactive component loses its store of energy over time, resulting in either a measurable decrease of voltage (capacitor) or current (inductor)
  • The more power dissipated by the resistor, the faster discharging occurs. Thus, a transient circuit's time constant will be dependent upon the resistance of the circuit
  • A circuit's time constant will be less (faster discharging rate) if the resistance value is such that it maximizes power dissipation (rate of energy transfer into heat)
  • Capacitors and Energy
    capacitors are reservoirs of potential energy
  • Inductors and Energy
    inductors are reservoirs of kinetic energy
  • Thevenin's Theorem
    we can reduce any linear circuit to an equivalent of one voltage source, one series resistance, and a load component
  • Applying Thevenin's Theorem
    1. regard the reactive component as the load and remove it temporarily from the circuit to find Thevenin voltage and resistance
    2. re-connect the capacitor and solve for values of voltage or current over time