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Physics
Topic 2: Electricity
Electrical Power and Energy
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Cards (21)
Why is understanding electrical power and energy important in GCSE Physics?
It is crucial for grasping how
electrical systems
work and how energy is used in various applications.
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What is the definition of electrical power?
Electrical power is the rate at which
electrical energy
is transferred or converted into another form of energy.
Measured in
watts
(W).
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What is the formula for electrical power?
P
=
P =
P
=
V
×
I
V \times I
V
×
I
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What do the variables in the power formula represent?
P
=
P =
P
=
Power (W)
,
V
=
\text{Power (W)}, V =
Power (W)
,
V
=
Voltage (V)
,
I
=
\text{Voltage (V)}, I =
Voltage (V)
,
I
=
Current (A)
\text{Current (A)}
Current (A)
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What is one watt defined as?
One
joule
of energy transferred per
second
.
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How can power be expressed in circuits with resistors?
\(
P
=
I^2
\times
R
\)
\(P = \frac{
V^2
}{R}\)
Where \(R\) is resistance in
Ohms
(
Ω
).
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What is the definition of electrical energy?
Energy consumed by
electrical devices
or produced by electrical systems over time.
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What is the formula for electrical energy?
E
=
E =
E
=
P
×
t
P \times t
P
×
t
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What do the variables in the energy formula represent?
E
=
E =
E
=
Energy (J)
,
P
=
\text{Energy (J)}, P =
Energy (J)
,
P
=
Power (W)
,
t
=
\text{Power (W)}, t =
Power (W)
,
t
=
Time (s)
\text{Time (s)}
Time (s)
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How do you convert energy to kilowatt-hours?
E
(
kWh
)
=
E (\text{kWh}) =
E
(
kWh
)
=
P
(
kW
)
×
t
(
h
)
1000
\frac{P (\text{kW}) \times t (\text{h})}{1000}
1000
P
(
kW
)
×
t
(
h
)
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What is the power consumed by a device that operates at 120V and draws a current of 3A?
360W
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How much energy does a heater that consumes 1500W of power use for 2 hours?
10,800,000J
or
10.8 MJ
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What is efficiency in the context of electrical devices?
Efficiency measures how much of the
electrical energy
supplied is converted into
useful energy output
.
Expressed as a
percentage
.
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What is the formula for calculating efficiency?
Efficiency
(
%
)
=
\text{Efficiency} (\%) =
Efficiency
(
%
)
=
(
Useful Power Output
Total Power Input
)
×
100
\left( \frac{\text{Useful Power Output}}{\text{Total Power Input}} \right) \times 100
(
Total Power Input
Useful Power Output
)
×
100
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What are some practical applications of understanding electrical power and energy?
Home appliances:
Calculating
energy consumption
and
costs
.
Renewable energy: Evaluating
energy efficiency
in
solar panels
and
wind turbines
.
Electric vehicles
: Understanding power used in charging and energy efficiency of
motors
.
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What is the summary of electrical power and energy concepts?
Electrical Power
:
Rate of energy transfer
, calculated as \(P = V \times I\).
Electrical Energy: Total energy consumed over time, calculated as \(E = P \times t\).
Efficiency
: Assesses how effectively devices use energy.
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What is the power consumed by a device that operates at 240V and has a current of 2.5A?
P
=
P =
P
=
240
V
×
2.5
A
=
240V \times 2.5A =
240
V
×
2.5
A
=
600
W
600W
600
W
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How much energy does a light bulb using 60W of power for 5 hours consume in kilowatt-hours?
E
=
E =
E
=
60
W
×
(
5
hours
×
3600
seconds/hour
)
=
60W \times (5 \text{ hours} \times 3600 \text{ seconds/hour}) =
60
W
×
(
5
hours
×
3600
seconds/hour
)
=
1080
Wh
=
1080 \text{ Wh} =
1080
Wh
=
1.08
kWh
1.08 \text{ kWh}
1.08
kWh
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If a resistor has a resistance of 8Ω and carries a current of 4A, what is the power dissipated in the resistor?
P
=
P =
P
=
I
2
×
R
=
I^2 \times R =
I
2
×
R
=
4
A
2
×
8
Ω
=
4A^2 \times 8Ω =
4
A
2
×
8Ω
=
128
W
128W
128
W
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If a kettle with a power rating of 3000W is used for 10 minutes, how much energy does it consume in kilowatt-hours?
E
=
E =
E
=
3000
W
×
(
10
minutes
×
60
seconds/minute
)
=
3000W \times (10 \text{ minutes} \times 60 \text{ seconds/minute}) =
3000
W
×
(
10
minutes
×
60
seconds/minute
)
=
1800000
J
=
1800000 \text{ J} =
1800000
J
=
0.5
kWh
0.5 \text{ kWh}
0.5
kWh
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If an appliance has a total power input of 1000W and outputs 800W of useful energy, what is its efficiency?
Efficiency
(
%
)
=
\text{Efficiency} (\%) =
Efficiency
(
%
)
=
(
800
W
1000
W
)
×
100
=
\left( \frac{800W}{1000W} \right) \times 100 =
(
1000
W
800
W
)
×
100
=
80
%
80\%
80%
View source
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