What shape do alkanes take around each carbon atom?
They adopt a tetrahedral shape and therefore have a bond angle of 109.5°. This is bc each C atom is bonded to 3 H atoms and another C angle so there are 4 bonding pairs of electrons.
How does the boiling point of alkanes change with carbon-chain length?
The boiling point increases as there is a greater surface area so more there is more surface contact between the molecules. Since London force act between molecules that are in close surface contact the molecules will be greater so more energy is required to overcome them.
How does branching affect the boiling point within alkanes
With more branches there is a decrease in surface area of contact which results in weaker London forces and hence a lower boiling point. The branches get in the way and prevent branched molecules from getting closer to the straight-chain = less intermolecular forces.
Alkanes are not very reactive. Their C-C and C-H bonds are σ-bonds which are strong - require large amounts of energy to brea so a high bond enthalpy. Their C-C bonds are non-polar and the C-H bonds are not polar since their electronegativity values are similar.
In a limited oxygen supply, there is not enough oxygen for the fuel to completely burn. As a result CO is produced which is poisonous when inhaled or just C particulates (Soot).
UV light provides enough vibration for the bond to break; which leads to homolytic fission when a bond breaks and one e- ends up in each atom (Shown by curly arrows). At this point the reaction is at equilibrium.
What happens in the termination stage?Two radicals collide to form a molecule with all e- pairs. When they collide both radicals react and are removed from the reaction mixture.
What is the limitation of free radical substitution? 1
At the propagation stage further substitution can occur. For example in methane we form chloromethane but this can be then be further substituted until all hydrogens are replaced with CL.
What is the limitation of free radical substitution? 2
Also, with longer carbon chains a mixture of monosubstitutedisomers will be created. Which will create different properties hence why it's not ideal to use it to synthesis one organic compound.
- After CH3Br is formed, another bromine radical can collide with a bromomethane molecule, substituting a further H atom to form dibromomethane, CH2Br2.
- Can continue until all H atoms have been substituted.