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chemistry
acids and bases
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Created by
lucy bosley
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Cards (5)
strong acid
−
log
10
(
H
+
)
=
-\log_{10}\left(H+\right)\ =
−
lo
g
10
(
H
+
)
=
p
H
\ pH
p
H
weak acid
K
a
=
Ka\ =
K
a
=
(
H
+
)
2
(
H
A
)
\ \frac{\left(H+\right)^2}{\left(HA\right)}
(
H
A
)
(
H
+
)
2
strong base
K
w
=
Kw=
K
w
=
(
H
+
)
(
O
H
−
)
\left(H^+\right)\left(OH^-\right)
(
H
+
)
(
O
H
−
)
buffer
(
weak acid
+ salt)
(
H
+
)
=
\left(H^+\right)=
(
H
+
)
=
K
a
(
H
A
)
(
A
−
)
\ \frac{Ka\ \left(HA\right)}{\left(A^-\right)}
(
A
−
)
K
a
(
H
A
)
H
A
HA
H
A
= conc of weak acid
A
−
A^-
A
−
= conc of salt of weak acid
buffer
(
weak acid
+
strong base
)
(
H
+
)
=
\left(H^+\right)=
(
H
+
)
=
(
H
+
)
(
H
A
)
(
A
−
)
\frac{\left(H^+\right)\ \left(HA\right)}{\left(A^-\right)}
(
A
−
)
(
H
+
)
(
H
A
)
H
A
=
HA\ =
H
A
=
how much left
A
−
A^-
A
−
= how much made
