What are the three factors that influence alkene stability?
Degree of substitution (more highly substituted=more stable)
Stereochemistry: trans > cis b/c of reduced steric interactions
Conjugated alkenes are more stable than isolated alkenes
3 bonding changes occur during eliminations:
a bond breaks H to C
A new pi bond forms C to C
a bond breaks C to LG
E2?
A concerted process, with a rate of reaction = k[base][R-LG].
base attacks H and breaks H-C bond causing the formation of a pi C-C bond and the C-LG bond to break.
E1?
C-Lg bond breaks first to form intermediate (carbocation), and then loss of proton to form pi bond between C-C+
reaction order of E1?
Tertiary>Secondary>Primary> methyl to stabilize carbocation
reaction order of E2?
Tertiary, secondary, primary, methyl because 2 sp3 atoms will be converted into sp2 atoms...
Eliminations often favour trans-product over the cis-product for stability
Zaitsev's rule?
Preference for elimination to give the more highly substituted (more stable) alkene which is known as Zaitsev's product
Increasing the size (sterics) of the base tends to increase the yield of the Hofmann (anti-zaitsev) product.
Better leaving group will increase yield of Zaitsev product
Zaitsev's rule also says that the carbon more likely to be deprotonated is the carbon with few hydrogens to begin with
A sterically hindered base cannot effectively react with the tertiary H, so it will instead deprotonate the primary carbon leading to the formation of the anti-Zaitsev or hofmann product
The higher the heat of combustion, the higher energy that the product is and thus the less stable the product is
More alkyl groups on the c=c double unit make it more stable because alkyl groups are weak electron donors that can stabilize sp2C...
In E2 reactions, there is a preference for the H-C and C-LG bonds to be coplanar and 180 degrees from each pther to help position the sigma bond about to break in the correct orientation to make a pi bond. AKA being in antiperiplanar conformation
Synperiplanar arrangments where the angle between the H-C bond and C-LG is 0o are also known, usually in systems that are either inflexible rings or intramolecular eliminations
In cyclic systems, the LG has to be axial in order to be anti to the C-H bond for E2
strong nucleophiles but weak bases: CN, N3, Cl, Br I, SH, SR (all negatively charged ions)