Save
AP Physics Midterm Review
Save
Share
Learn
Content
Leaderboard
Learn
Created by
SparklingLemur40154
Visit profile
Cards (52)
average velocity
displacement
/
change in time
(△x/△t)
instantaneous velocity
lim
of
displacement
/
change
in
time
average speed
total distance
/
time
average acceleration
change in
velocity
/ change in
time
(△v/△t)
instantaneous acceleration
lim of change in velocity / change in time
speeding up
v and a have same sign
slowing down
v and
a have
opposite
signs
position from velocity equation
integral
from
x initial
to
x final
of
v
(t)
1-D Kinematic Equations (
given
on equation sheet)
v =
v0
+
atx
=
x0
+
v0t
+
1/2at^2v^2
=
v0^2
+
2a(change in x)
free fall
motion
of an object
exclusively
under the
influence
of the
force
of
gravity
3 possibilities for 1-D free fall
If +y is
upward
:object
dropped
from
rest
(v0 = 0)object thrown
downward
(v0 = negative)object thrown
upward
(v0 = positive)
plots of
position
and
velocity
v time with differing
accelerations
expression for vector A in terms of x and y components
vector A = (A
cos x
)i + (A
sin x
)
jwhere
A
is
the
hypotenuse
of
triangle
made by vector A's
x
and y components
magnitude of vector
A
A
= √(
Ax
)^
2
+ (
Ay
)^
2
Componentwise
Addition
of Vectors (C, A,
B
)
Cx = Ax + BxCy =
Ay
+
By
2-D Kinematics General Equations
r(t) = x(t)i + y(t)jch.
r = (ch. x)i + (ch. y)javerage velocity vector = (ch. x/ch.t)i + (ch. y/ch.t)jinstantaneous velocity vector = (vx)i + (vy)j = (dx/dt)i + (dy/dt)jinstantaneous acceleration = (ax)i + (ay)j = (d^2x/dt^2)i + (d^2y/dt^2)j
In 2-D projectile motion w constant a: horizontal component of the initial velocity (vx0)
vx0 = v0 cos x
In 2-D projectile motion w constant a: vertical component of the initial velocity (vy0)
vy0 =
v0 sin x
In 2-D projectile motion:
horizontal component
of the
acceleration
(
ax
)
ax =
0
In
2-D
projectile Motion:
vertical
component of the
acceleration
(
ay
)
ay =
-g
In 2-D projectile motion w constant a: vertical component of velocity (vy) at maximum height
vy =
0
2-D Kinematic Equations for Horizontal Component of Projectile Motion
vx
=
v0 cos
x (
constant
)
ch. x
= (
v0 cos
x)t
2-D Kinematic Equations for Vertical Component of Projectile Motion
vy =
v0 sin
x
- gtch.
y = (
v0 sin x
)t
- 1/2gt^2
mechanical
equilibrium
object has
constant
velocity and
zero
acceleration
mass
a measure of an object's
resistance
to changes in
velocity
(
lower
mass means more
susceptible
to changes in velocity)
force
push or pull,
nonzero
net force causes an object to
accelerate
(If m1 > m2,
a1
<
a2
)
Newton's First Law
In
absence
of a
net force
, object at
rest
will remain at
rest
and an object in
motion
will continue to move in the same
direction
at the same
speed
Newton's Second Law
F
=
ma
Newton's Third Law
The force that A exerts on B is
equal
in
magnitude
and
opposite
in
direction
to the
force
that
B exert
on
A
Relationship between the coefficients of
static
and
kinetic friction
us
>
uk
How to determine which way
friction vector points
ask how the object would move in the
absence
of
friction
uniform circular motion
particle travels with
constant linear speed
(v) in a
circular
pathparticle's
velocity
vector is always tangent to the
circular
path
magnitude and direction of
acc
. vector in UCM (
given
on equation sheet)
a = v^
2
/ racc. vector points
toward
the
center
of the
circle
centripetal force
not a new force but can be the force of tension, friction, gravitation, normal force, etc.
Relationship between centripetal force and
centripetal
acceleration
F
=
mv^2
/ r
Period of rotation (
given
on equation sheet)
T =
2pir
/ v
work
(
N * m
)
mechanism
by which
energy
is
transferred
to an
object
via the
application
of a
force
while
object
undergoes
displacement
positive work
F points in the same direction as displacement (facilitates motion)
negative work
F points in the opposite direction as displacement (
opposes motion
)
power
(
W
)
the rate at which work is done
See all 52 cards