Practice questions

• Answer

  Equatorial orbit

  Orbital period of 24hrs


  Questions

  
• Answer

  Equatorial orbit

  Orbital period of 24 hrs

  R^3 = T^2 * G * m/4 * pi 


  Question

  
• Answer

  (a) Resultant force acts perpendicular to the direction of motion~

  (b) Constantly changing direction therefore velocity acceleration is towards the centre of the circle

  GMm/r^2 = mv^2/r = Gm/v^2 = 2.92


  Question

  
• Answer

  Force per unit mass

  G * r^2 = constant + plug in for each value


  Question