Cards (67)

  • The velocity of an object is the derivative of its position
  • The acceleration of an object is the second derivative of its position
  • What is the relationship between position, velocity, and acceleration?
    Derivative relationships
  • What is the formula to find acceleration from velocity?
    a(t)=a(t) =dv/dt dv / dt
  • What is the formula for velocity in terms of position?
    v(t)=v(t) =ds/dt ds / dt
  • What is the second derivative of position called?
    Acceleration
  • The velocity function v(t)=v(t) =6t4 6t - 4 means the particle's velocity changes over time.

    True
  • The acceleration of an object is the derivative of the velocity
  • If s(t) = t^3 - 6t^2 + 9t, the velocity is v(t) = 3t^2 - 12t + 9

    True
  • What is the relationship between velocity and position?
    Velocity is ds/dt
  • What does a positive value of acceleration indicate about an object's velocity?
    Velocity is increasing
  • Under what condition is an object considered at rest?
    Velocity is zero
  • In which interval is the speed decreasing when v(t) = t^2 - 4t + 3 and a(t) = 2t - 4?
    2 < t < 3
  • The derivative of position is velocity
  • What is the acceleration if s(t) = t^3 - 6t^2 + 9t?
    6t - 12
  • The formula for velocity in terms of position is v(t) = ds/dt
  • The acceleration of an object is the derivative of its velocity.

    True
  • What does a negative value of acceleration indicate about an object's velocity?
    Velocity is decreasing
  • A negative value of acceleration means the object's velocity is decreasing.

    True
  • If v(t) = t^2 - 4t + 3, the object is at rest when t = 1 or t = 3.

    True
  • Speed increases when v(t) and a(t) have the same sign.

    True
  • Steps to determine when an object is stationary, moving forward, or backward using v(t) = t - 2
    1️⃣ Solve v(t) = 0 to find stationary points
    2️⃣ Solve v(t) > 0 to find forward motion
    3️⃣ Solve v(t) < 0 to find backward motion
  • What is the formula for calculating displacement?
    Δs = s(b) - s(a)
  • Match the concept with its characteristic:
    Displacement ↔️ Positive or negative sign
    Distance Traveled ↔️ Always positive
  • What is the average velocity of the object from t = 0 to t = 4 if s(t) = t^3 - 6t^2 + 9t?
    -1
  • What is the mathematical relationship between velocity and acceleration?
    a(t)=a(t) =dv/dt dv / dt
  • Velocity is found by differentiating the position function.
    True
  • The velocity of an object is the rate of change of its position
  • The position of an object is defined as its location
  • If the position function is s(t) = 3t^2 - 4t + 1</latex>, what is the velocity function?
    v(t)=v(t) =6t4 6t - 4
  • What is the acceleration function if the velocity function is v(t)=v(t) =3t212t+ 3t^{2} - 12t +9 9?

    a(t)=a(t) =6t12 6t - 12
  • The acceleration of an object is the derivative of its velocity
  • The position of an object is represented by s(t), where t is time
    True
  • Steps to analyze motion using velocity and acceleration functions
    1️⃣ Find when v(t) = 0 to determine rest points
    2️⃣ Determine when v(t) > 0 or v(t) < 0 to find direction
    3️⃣ Calculate a(t) = dv/dt
    4️⃣ Analyze the signs of v(t) and a(t) to find when speed is increasing or decreasing
  • An object is moving forward when its velocity is negative.
    False
  • Speed increases when velocity and acceleration have opposite signs.
    False
  • At what time is an object stationary if v(t) = t - 2?
    t = 2
  • What is the velocity if s(t) = t^3 - 6t^2 + 9t?
    3t^2 - 12t + 9
  • What is the velocity if v(t) = ds/dt and s(t) = 3t^2 - 4t + 1?
    v(t) = 6t - 4
  • The acceleration is the rate of change of velocity