6.1. Electric Fields

• Coulomb's law is used to calculate electric field strength
• Match the key aspect with its description:

  Definition ↔️ Region surrounding a charged object exerting a force

  Type ↔️ Vector field

  Properties ↔️ Strength and direction

  Target ↔️ Test charge
• What is electric force?

  Force due to charge
• Faraday's Law of Induction states that a changing magnetic field induces an electric field
• Match the source of electric fields with its description:

  Stationary Charges ↔️ Charges at rest create electric fields

  Changing Magnetic Fields ↔️ Changing magnetic fields induce electric fields
• What formula describes the electric field created by stationary charges?

  $E =$$\frac{kQ}{r^{2}}$
• What is the value of Coulomb's constant \( k \)?

  $8.988 \times 10^{9} \text{ Nm}^{2} / \text{C}^{2}$
• An electric field is a vector field with both magnitude and direction.


  True
• The electric field for a positive charge points radially outward
• How does the strength of the electric field change with distance from a point charge?

  Decreases with the square
• What is the symbol for Coulomb's constant in the electric field equation?

  k
• For a negative charge, the electric field points radially inward.


  True
• The equation F = qE describes the relationship between electric force, charge, and electric field.


  True
• Steps in creating an electric field using a changing magnetic field

  1️⃣ Change the magnetic field

  2️⃣ Induce an electric field

  3️⃣ Apply Faraday's Law of Induction
• What is the direction of the electric field for a positive charge?

  Radially outward
• Match the charge polarity with its electric field direction:

  Positive ↔️ Radially outward

  Negative ↔️ Radially inward
• Electric fields originate from electric charges and the direction of the field depends on the charge polarity.

  True
• Match the charge polarity with the electric field direction:

  Positive charge ↔️ Radially outward

  Negative charge ↔️ Radially inward
• The value of Coulomb's constant is $8.988 \times 10^{9}$ Nm²/C².


  True
• Steps to calculate electric field strength near a single point charge

  1️⃣ Use Coulomb's law to find the electric force

  2️⃣ Apply the formula $E =$$\frac{F}{q}$ to find electric field strength
• What do electric field lines visualize?

  Strength and direction
• Electric field lines originate from positive charges and terminate on negative
• Stationary charges create electric fields that are described by the equation E = \frac{kQ}{r^2}</latex>, where $k$ is Coulomb's constant
• What principle is electromagnetic induction based on?

  Faraday's Law
• An electric field is a scalar field characterized by magnitude only.

  False
• The direction of an electric field created by a positive charge is radially inward.

  False
• Electric field strength is defined as the force per unit charge
• The value of Coulomb's constant \( k \) is \( 8.988 \times 10^9 \) Nm²/C², which is approximately 9 × 10⁹ Nm²/C².
• In Example 1, the point charge has a value of 5 µC.
• Match the variable with its value from Example 1:

  \( Q_1 \) ↔️ 5 µC

  \( r \) ↔️ 2 m
• The point charge in Example 1 has a value of 5 µC.
• Coulomb's law describes the force between two charges separated by a distance \( r \).

  True
• The electric force calculated in Example 1 is 11.24 N.

  True
• Electric field strength is defined as the force experienced per unit charge.


  True
• Coulomb's law applies only to static charges.


  True
• What is the value of \( Q_1 \) in Example 1?

  5 µC
• In Example 2, the electric field due to \( Q_1 \) at location P is \( 6741 \, N/C \) to the right.
• What is the electric field strength due to \( Q_1 \) in Example 2 at point P?

  6741 N/C to the right
• In Example 2, the electric field due to \( Q_2 \) at location P is \( -8988 \, N/C \) to the right.
• What is the point charge in Example 1?

  5 µC