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AP Statistics
Unit 4: Probability, Random Variables, and Probability Distributions
4.12 The Geometric Distribution
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Cards (56)
What type of probability distribution is the geometric distribution?
Discrete
In the PMF formula, `k` represents the number of
trials
The variance of the geometric distribution is
1
−
p
p
2
\frac{1 - p}{p^{2}}
p
2
1
−
p
.
True
What is the term for independent trials with only two possible outcomes in a geometric random variable?
Bernoulli trials
Match the property with its corresponding formula or description for a geometric random variable:
PMF ↔️
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
∗
(1 - p)^(k - 1) *
(
1
−
p
)
(
k
−
1
)
∗
p
p
p
Mean ↔️
1
p
\frac{1}{p}
p
1
Variance ↔️
1
−
p
p
2
\frac{1 - p}{p^{2}}
p
2
1
−
p
What is the probability mass function (PMF) of the geometric distribution?
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
∗
(1 - p)^(k - 1) *
(
1
−
p
)
(
k
−
1
)
∗
p
p
p
What does the term (1 - p)^(k - 1) represent in the PMF of the geometric distribution?
Probability of failures
Match the term with its description in the PMF of the geometric distribution:
X ↔️ Geometric random variable
k ↔️ Number of trials
p ↔️ Probability of success
The geometric random variable X represents the number of trials needed to achieve the
first success
.
True
The term (1 - p)^(k - 1) in the geometric PMF represents the probability of (k - 1)
consecutive failures
.
True
The geometric distribution models the number of trials needed to achieve the first
success
The trials in a geometric distribution are independent
Bernoulli trials
.
True
What is the formula for the probability mass function (PMF) of the geometric distribution?
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
∗
(1 - p)^(k - 1) *
(
1
−
p
)
(
k
−
1
)
∗
p
p
p
What is the mean of the geometric distribution?
1
p
\frac{1}{p}
p
1
Match the property with its value for the geometric distribution:
Mean ↔️
1
p
\frac{1}{p}
p
1
Variance ↔️
1
−
p
p
2
\frac{1 - p}{p^{2}}
p
2
1
−
p
PMF ↔️
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
∗
(1 - p)^(k - 1) *
(
1
−
p
)
(
k
−
1
)
∗
p
p
p
A geometric random variable represents the number of trials needed to achieve the first
success
The probability of success in each Bernoulli trial of a geometric
random variable
is denoted as 'p'.
True
Steps to identify the characteristics of a geometric random variable:
1️⃣ Check for independent Bernoulli trials
2️⃣ Identify the constant probability of success 'p'
3️⃣ Determine the number of trials until the first success
The geometric distribution assumes that the trials are independent and each has the same
probability
of success.
True
The geometric distribution is useful for modeling situations where we are interested in the number of trials needed to obtain the first
success
The geometric distribution is a continuous probability distribution.
False
Match the property with its formula for the geometric distribution:
Mean ↔️
1
p
\frac{1}{p}
p
1
Variance ↔️
1
−
p
p
2
\frac{1 - p}{p^{2}}
p
2
1
−
p
The probability mass function (PMF) of the geometric distribution is
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
∗
(1 - p)^(k - 1) *
(
1
−
p
)
(
k
−
1
)
∗
p
p
p
.
True
If you roll a fair die until you get a 6, the number of rolls needed follows a geometric distribution with
p = \frac{1}{6}
What is the probability mass function (PMF) of the geometric distribution?
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
⋅
p
(1 - p)^{(k - 1)} \cdot p
(
1
−
p
)
(
k
−
1
)
⋅
p
Steps to interpret the PMF formula of the geometric distribution:
1️⃣ Recognize (1 - p)^(k-1) as the probability of (k-1) failures
2️⃣ Recognize p as the probability of the first success on the k-th trial
The term 'p' in the geometric distribution represents the probability of
success
What does the term 'k' represent in the geometric distribution?
Number of trials
What does the term 'p' in the geometric PMF represent?
Probability of success on the k-th trial
The mean of the geometric distribution is
1/p
What is the variance of the geometric distribution?
1
−
p
p
2
\frac{1 - p}{p^{2}}
p
2
1
−
p
What is the probability of obtaining the first success on the 5th trial if the probability of success is 0.2?
0.1024
The geometric distribution models the number of trials needed to achieve the first success in a sequence of independent
Bernoulli
trials.
In Bernoulli trials, there are only two possible outcomes: success or failure.
True
What does the geometric random variable 'X' represent?
Number of trials until first success
The PMF of the geometric distribution is
P
(
X
=
k
)
=
P(X = k) =
P
(
X
=
k
)
=
(
1
−
p
)
(
k
−
1
)
⋅
p
(1 - p)^{(k - 1)} \cdot p
(
1
−
p
)
(
k
−
1
)
⋅
p
True
In the PMF formula, `X` is the geometric random variable representing the number of trials needed to achieve the first
success
The term
(
1
−
p
)
(
k
−
1
)
(1 - p)^{(k - 1)}
(
1
−
p
)
(
k
−
1
)
in the PMF formula represents the probability of (k-1) consecutive failures before the first success.
True
The term `p` in the PMF formula represents the probability of the first success on the
k-th
trial.
The variance of the geometric distribution is
(1 - p) / p^2
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