10.7 Electric Flux

• What does electric flux measure?

  Electric field lines
• Match the concept with its description:

  Definition ↔️ Measures electric field lines passing through an area

  Formula ↔️ $\Phi_{E} =$$E \cdot A \cdot \cos(\theta)$

  Units ↔️ Volt-meters (V·m)
• What is the value of the permittivity of free space (\(\epsilon_0\))?

  8.854 \times 10^{-12}</latex> C²/N·m²
• The permittivity of free space (\(\epsilon_0\)) has a value of $8.854 \times 10^{ - 12}$
• Steps to calculate electric flux using Gauss's Law

  1️⃣ Determine the enclosed charge (\(Q_{enc}\))

  2️⃣ Use the value of permittivity of free space (\(\epsilon_0\))

  3️⃣ Apply Gauss's Law to find the electric flux
• What is the unit for electric flux?

  Volt-meters
• A larger area always results in less electric flux through a surface.

  False
• The angle θ in the electric flux formula is between the electric field and the normal vector of the surface.

  True
• The formula for Gauss's Law is \Phi_{E} = Q_{enc} / \epsilon_{0}
• If a closed surface contains a charge of \(5 \times 10^{-6}\) C, the electric flux is approximately 5.65 \times 10^{5} V·m
• What is the formula for Gauss's Law relating electric flux (\(\Phi_{E}\)), enclosed charge (\(Q_{enc}\)), and permittivity of free space (\(\epsilon_0\))?

  $\Phi_{E} =$$\frac{Q_{enc}}{\epsilon_{0}}$
• The formula for electric flux through an open surface is $\Phi_{E} =$$E \cdot A \cdot \cos(\theta)$ where \(E\) is the electric field, \(A\) is the area, and \(\theta\) is the angle between the field and the normal vector to the surface.


  True
• The formula for electric flux (\(\Phi_E\)) is $\Phi_{E} =$$E \cdot A \cdot \cos(\theta)$
• Match the variable in Gauss's Law with its description:

  \(\Phi_{E}\) ↔️ Total electric flux through the surface

  \(Q_{enc}\) ↔️ Total charge enclosed within the surface

  \(\epsilon_0\) ↔️ Permittivity of free space
• Electric flux through a closed surface is calculated using Gauss's Law
• Steps to calculate electric flux

  1️⃣ Identify the enclosed charge

  2️⃣ Use the permittivity of free space

  3️⃣ Apply Gauss's Law
• Electric flux measures the number of electric field lines passing through a surface.

  True
• The formula for Gauss's Law is \Phi_{E} = \frac{Q_{enc}}{\epsilon_{0}}
• A spherical Gaussian surface is used to enclose line charges.

  False
• What is the key principle of Gauss's Law?

  Relates flux to charge
• What is the definition of electric flux in physics?

  Electric field lines through a surface
• What are the units of electric flux?

  Volt-meters
• What is the formula to calculate electric flux through a closed surface using Gauss's Law?

  \Phi_E = \frac{Q_{enc}}{\epsilon_0}</latex>
• Match the method with its use:

  Gauss's Law ↔️ For symmetric geometries enclosing charge

  Direct Integration ↔️ For complex shapes without simple symmetry
• What is the first step in applying Gauss's Law to solve a problem?

  Choose a Gaussian surface
• The formula for electric flux is \Phi_{E} = E \cdot A \cdot \cos(\theta)
• What does Gauss's Law relate electric flux to?

  Enclosed charge
• Steps to calculate electric flux using Gauss's Law

  1️⃣ Determine the enclosed charge

  2️⃣ Use the value of permittivity of free space

  3️⃣ Apply Gauss's Law to find the electric flux
• Electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space.

  True
• Electric flux measures the amount of electric field passing through a surface
• Match the factor affecting electric flux with its effect:

  Electric field strength ↔️ Stronger field means more flux

  Area size ↔️ Larger area means more flux

  Angle ↔️ Perpendicular alignment maximizes flux
• What does Gauss's Law state regarding electric flux through a closed surface?

  Charge enclosed divided by \(\epsilon_0\)
• The formula for Gauss's Law is $\Phi_{E} =$$\frac{Q_{enc}}{\epsilon_{0}}$.


  True
• The permittivity of free space is approximately 8.854
• Gauss's Law states that the total electric flux through a closed surface is equal to the charge enclosed divided by the permittivity of free space
• What does the permittivity of free space quantify?

  Electric field behavior
• A spherical Gaussian surface encloses a charge of 2 x 10^-6 C.
• Match the factors affecting electric flux with their descriptions:

  Electric Field Strength ↔️ Stronger field means more flux

  Area Size ↔️ Larger area means more flux

  Angle ↔️ Alignment perpendicular to the field gives maximum flux
• What is the purpose of the permittivity of free space in Gauss's Law?

  Defines electric field behavior
• Gauss's Law relates the electric flux through a closed surface to the total charge enclosed within that surface.

  True