5.1 Using the Mean Value Theorem

    Cards (60)

    • The average rate of change of a function over the interval [a, b] is equal to the instantaneous rate of change at some point c
    • What are the two conditions required for the Mean Value Theorem to hold true for a function f(x) over an interval [a, b]?
      Continuity and differentiability
    • Order the steps to apply the Mean Value Theorem:
      1️⃣ Verify continuity on [a, b]
      2️⃣ Verify differentiability on (a, b)
      3️⃣ Calculate the average rate of change (f(b) - f(a))/(b - a)
      4️⃣ Find the point c such that f'(c) = (f(b) - f(a))/(b - a)
    • What are the two conditions required for the Mean Value Theorem (MVT) to hold true for a function f(x) over an interval [a, b]?
      Continuity and differentiability
    • Match the condition with its requirement for the Mean Value Theorem:
      Continuity ↔️ f(x) must be continuous on [a, b]
      Differentiability ↔️ f(x) must be differentiable on (a, b)
    • In the Mean Value Theorem formula, f(b) - f(a) represents the change in the function value over the interval [a, b].

      True
    • Match the component of the Mean Value Theorem formula with its description:
      f(b) - f(a) ↔️ Change in function value
      b - a ↔️ Interval length
      (f(b) - f(a)) / (b - a) ↔️ Average rate of change
      f'(c) ↔️ Instantaneous rate of change at point c
    • In Example 1, the Mean Value Theorem guarantees the existence of a point c in (1, 5) where f'(c) = 3.

      True
    • For the quadratic function, the value of c guaranteed by the Mean Value Theorem is 1.5.
      True
    • For the function f(x)=f(x) =x22x+ x^{2} - 2x +1 1, the value of cc that satisfies the MVT in the interval (1,2)( - 1, 2) is 1.51.5.

      True
    • What does the Mean Value Theorem (MVT) state if a function f(x) is continuous on [a, b] and differentiable on (a, b)?
      f'(c) = (f(b) - f(a))/(b - a)
    • Match the theorem with its key idea:
      Mean Value Theorem (MVT) ↔️ The average rate of change equals the instantaneous rate of change
      Intermediate Value Theorem (IVT) ↔️ A continuous function must pass through zero if it changes sign
    • What does differentiability on the open interval (a, b) imply for the function f(x)?
      The derivative exists
    • What is the second condition required for the Mean Value Theorem, and on which interval must it hold?
      Differentiability on (a, b)
    • The Mean Value Theorem requires f(x) to be differentiable on the open interval (a, b).

      True
    • The formula for the Mean Value Theorem is \frac{f(b) - f(a)}{b - a}
    • The Mean Value Theorem states that there exists a point c in the interval (a, b) where f'(c) is equal to the average rate of change
    • The average rate of change for the linear function f(x) = 2x + 3 over [1, 5] is 3
    • The average rate of change for the quadratic function over [-1, 2] is 1
    • By the Mean Value Theorem, there exists a point c in the open interval (1,2)( - 1, 2) such that f(c)=f'(c) =1 1.
    • The Mean Value Theorem states that if a function f(x)f(x) is continuous on [a, b], it must also be differentiable on (a,b)(a, b).
    • What does the Intermediate Value Theorem state about continuous functions?
      They must pass through zero
    • The function f(x)f(x) must be differentiable on the open interval (a,b)(a, b) to satisfy the Mean Value Theorem.

      True
    • The term bab - a in the MVT formula represents the length of the interval.
    • In the MVT formula, f(c)f'(c) represents the instantaneous rate of change at the point c.
    • For the quadratic function f(x)=f(x) =x24x+ x^{2} - 4x +5 5, the value of cc that satisfies the MVT in the interval (1,3)(1, 3) is 2.
    • Rolle's Theorem states that if a function f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), and f(a) = f(b), then there exists at least one point c in (a, b) such that f'(c) = 0
    • For Rolle's Theorem to hold, the function must start and end at the same y-value
    • What is the average rate of change for f(x) = x^3 - 3x + 2 on the interval [-2, 2]?
      1
    • Both values of c ≈ ±1.15 for f(x) = x^3 - 3x + 2 are within the interval (-2, 2).

      True
    • The value of c ≈ 0.69 for f(x) = cos(x) is within the interval (0, π).

      True
    • What is the formula for the Mean Value Theorem?
      \frac{f(b) - f(a)}{b - a} = f'(c)</latex>
    • Order the key ideas of the Mean Value Theorem and Intermediate Value Theorem:
      1️⃣ MVT: Average rate of change equals instantaneous rate of change at some point
      2️⃣ IVT: A continuous function must pass through zero if it changes sign
    • Match the condition for the MVT with its requirement:
      Continuity ↔️ f(x)f(x) must be continuous on [a,b][a, b]
      Differentiability ↔️ f(x)f(x) must be differentiable on (a,b)(a, b)
    • The MVT asserts that there exists a point cc in the interval (a,b)(a, b) where the instantaneous rate of change equals the average rate of change.

      True
    • The Mean Value Theorem guarantees that the instantaneous rate of change at some point cc is equal to the average rate of change over the interval [a,b][a, b].

      True
    • Rolle's Theorem is a special case of the Mean Value Theorem where f(a)=f(a) =f(b) f(b).

      True
    • Rolle's Theorem is a special case of the Mean Value Theorem.
      True
    • What is the first step to apply the Mean Value Theorem (MVT)?
      Verify the conditions
    • The derivative of f(x) = x^3 - 3x + 2 is 3x^2 - 3