The Product Rule states that \( \frac{d}{dx} [u(x) \cdot v(x)] = u'(x) \cdot v(x) + u(x) \cdot v'(x) \), where \( u'(x) \) is the derivative of \( u(x) \) and \( v'(x) \) is the derivative of \( v(x)
What is the derivative of \( x^2 \cdot \sin(x) \) using the Product Rule?
\( 2x \cdot \sin(x) + x^2 \cdot \cos(x) \)
When using the Product Rule, the first step is to identify the two functions being multiplied.
True
To apply the Product Rule formula, you must first identify \( u(x) \) and \( v(x) \) from the product
When differentiating \( x \cdot \ln(x) \) using the Product Rule, the derivative of \( \ln(x) \) is \( \frac{1}{x} \), and the derivative of \( x \) is 1
The derivative of \(f(x) = x \cdot \ln(x)\) is \(f'(x) = \ln(x) + 1
What is the derivative of \(f(x) = x^2 \cdot \sin(x) \cdot e^x\)?
2x\sin(x)e^x + x^2\cos(x)e^x + x^2\sin(x)e^x
The Product Rule formula is dxd[f(x)⋅g(x)]=f′(x)⋅g(x)+f(x)⋅g′(x)
True
Applying the Product Rule to \( x^2 \cdot \sin(x) \) results in \( 2x \cdot \sin(x) + x^2 \cdot \cos(x) \)
To apply the Product Rule, you must differentiate each function individually
If \( f(x) = x^2 \) and \( g(x) = \sin(x) \), what is the derivative of their product using the Product Rule?
2x⋅sin(x)+x2⋅cos(x)
If \( u(x) = x^2 \) and \( v(x) = \sin(x) \), what is the derivative of their product using the Product Rule?
2x⋅sin(x)+x2⋅cos(x)
To apply the Product Rule, you must differentiate each function
What is the key focus when applying the Product Rule?
Differentiate each function individually
The Product Rule formula is \(\frac{d}{dx} [u(x) \cdot v(x)]\)
The derivative of \( x \cdot \ln(x) \) is \( \ln(x) + 1 \)
True
The Product Rule can be extended to differentiate the product of more than two functions