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AP Calculus AB
Unit 1: Limits and Continuity
1.14 Connecting Infinite Limits and Vertical Asymptotes
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Cards (34)
What is a vertical asymptote?
Line function approaches
Infinite limits are mathematically represented as
lim
x
→
a
f
(
x
)
=
\lim_{x \to a} f(x) =
lim
x
→
a
f
(
x
)
=
±
∞
\pm \infty
±
∞
, where
∞
\infty
∞
denotes positive or negative infinity
Match the concept with its definition:
Infinite Limit ↔️ Limit approaches positive or negative infinity
Vertical Asymptote ↔️ Vertical line the function approaches
What happens to
f
(
x
)
=
f(x) =
f
(
x
)
=
1
x
−
3
\frac{1}{x - 3}
x
−
3
1
as
x
x
x
approaches 3 from the left?
f
(
x
)
→
−
∞
f(x) \to - \infty
f
(
x
)
→
−
∞
An infinite limit occurs when a function's values approach
infinity
as the input variable approaches a certain value.
True
What is the mathematical representation of an infinite limit?
\lim_{x \to a} f(x) = \pm \infty</latex>
Match the concept with its definition:
Infinite Limit ↔️ Values approach infinity
Vertical Asymptote ↔️ Line the function approaches
The presence of an infinite limit at
x
=
x =
x
=
a
a
a
indicates a vertical asymptote at
x
=
x =
x
=
a
a
a
As
x
x
x
approaches 3 from the right in f(x) = \frac{1}{x - 3}</latex>,
f
(
x
)
f(x)
f
(
x
)
approaches
∞
\infty
∞
True
What condition must be met for
x
=
x =
x
=
a
a
a
to be a vertical asymptote?
lim
x
→
a
f
(
x
)
=
\lim_{x \to a} f(x) =
lim
x
→
a
f
(
x
)
=
±
∞
\pm \infty
±
∞
For
f
(
x
)
=
f(x) =
f
(
x
)
=
1
x
−
2
\frac{1}{x - 2}
x
−
2
1
, where is the denominator zero?
x
=
x =
x
=
2
2
2
What is an infinite limit?
Limit approaches infinity
When do infinite limits occur?
Values approach infinity
What is a vertical asymptote in terms of function behavior?
A line function approaches
If a function has an infinite limit at
x
=
x =
x
=
a
a
a
, it also has a vertical asymptote at
x
=
x =
x
=
a
a
a
.
True
The presence of an infinite limit at
x
=
x =
x
=
a
a
a
indicates a vertical asymptote at x = a
Steps to identify vertical asymptotes using infinite limits:
1️⃣ Identify potential locations where the denominator is zero
2️⃣ Check for infinite limits as x approaches these values
3️⃣ Confirm vertical asymptotes if
lim
x
→
a
f
(
x
)
=
\lim_{x \to a} f(x) =
lim
x
→
a
f
(
x
)
=
±
∞
\pm \infty
±
∞
Vertical asymptotes are vertical lines that a function crosses but never touches.
False
What is an infinite limit in calculus?
Limit approaches infinity
What is a vertical asymptote?
Line function approaches but never touches
Steps to identify vertical asymptotes from infinite limits
1️⃣ Find values of
x
x
x
where the denominator of
f
(
x
)
f(x)
f
(
x
)
is zero
2️⃣ Evaluate limits as
x
x
x
approaches these values from both left and right
3️⃣ If
lim
x
→
a
f
(
x
)
=
\lim_{x \to a} f(x) =
lim
x
→
a
f
(
x
)
=
±
∞
\pm \infty
±
∞
, then
x
=
x =
x
=
a
a
a
is a vertical asymptote
To confirm a vertical asymptote, the limit as
x
x
x
approaches
a
a
a
must equal
±
∞
\pm \infty
±
∞
Match the concept with its definition:
Infinite Limit ↔️ Limit approaches infinity
Vertical Asymptote ↔️ Line function approaches but never touches
Vertical asymptotes can be identified by analyzing infinite
limits
Vertical asymptotes occur when a function has a vertical limit of positive or negative infinity at a
specific
input value.
True
Steps to find vertical asymptotes
1️⃣ Identify values where the denominator is zero
2️⃣ Check if the limit as
x
x
x
approaches those values is infinite
What is a vertical asymptote?
Line the function approaches
Match the concept with its definition:
Infinite Limit ↔️ Limit approaches infinity
Vertical Asymptote ↔️ Line the function approaches
Vertical asymptotes occur when the function's value approaches infinity as x approaches a certain
value
How are infinite limits and vertical asymptotes connected?
Infinite limits indicate vertical asymptotes
As
x
x
x
approaches 3 from the left in
f
(
x
)
=
f(x) =
f
(
x
)
=
1
x
−
3
\frac{1}{x - 3}
x
−
3
1
,
f
(
x
)
f(x)
f
(
x
)
approaches
−
∞
- \infty
−
∞
True
The presence of an infinite limit at
x
=
x =
x
=
a
a
a
indicates a vertical asymptote at
x
=
x =
x
=
a
a
a
The denominator of f(x) = \frac{1}{x - 4}</latex> is zero at
x
=
x =
x
=
4
4
4
True
The function
f
(
x
)
=
f(x) =
f
(
x
)
=
1
x
−
2
\frac{1}{x - 2}
x
−
2
1
has a vertical asymptote at
x
=
x =
x
=
2
2
2
True