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Paper 1
C3
Electrolysis
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Created by
Lewis Hills
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Cards (10)
Anode - positive electrode
attracts negative ions
oxidation
at the anode (ions lose
electrons
)
Cathode - negative electrode
attracts positive
ions
(Cat attract pawsitive)
Reducation at the cathode (ions gain electrons)
Cathode
Al2O3,
Aluminium Oxide
product =
aluminium
Half equation = Al (+3) +3e (-1) -> Al
Anode
Al2O3,
Aluminium Oxide
Product =
Oxygen
Half equation = 2O (-2) -> O2 + 4e (-1)
In aqueous solutions:
If H+ ions and metals ions are present,
hydrogen
gas will be produced if the metal is
more
reactive than
hydrogen
If the metal is
less
reactive than
hydrogen
, a solid layer of
pure
metal is produced instead
In aqueous solution:
If
halide
ions are present at the
anode
, molecules of the halide ion will be produced
If no halide ions are present, then
Oxygen
will be formed from the
hydroxide
ions
In aqueous solution, aswell as the ions from the ionic compound,
Hydrogen ions
(H+) and
Hydroxide ions
(OH-) will be present from the
water.
H2O -> H + OH
Non-inert electrodes can decompose into the electrolyte.
Eg.
Copper
electrodes in a solution of copper sulfate
Non-inert electrodes
Mass of
cathode
increases
Mass of
anode
decreases
This is because copper is transferred from the
anode
to the
cathode
Non-inert electrodes half equations:
Anode
:
Cu (s) -> Cu (+2) (aq) + 2e (-1)
Cathode
Cu (+2)(aq) + 2e (-1) -> Cu (s)