If Work done or energy are negative then the force is attractive.
Work is done when a force displaces an object through a certain distance.
Work done = F • S = F s cosθ.
1 Joule =1 Newton • 1 meter
The SI unit of work done is joules and CGS is erg.
Power is the rate of doing work, represented as P = W/t = Joule/sec = Watt.
Work done is scalar whereas force and displacement are vector quantities therefore we use dot product to calculate work done.
Power is also the rate of consumption of energy, represented as P = E/t = Joule/sec = Watt.
Work done by a variable force is represented as dW = F • dx.
If force is variable then calculus is used to calculate work done.
Work done can be positive, zero, or negative.
Force → displacement → work done → energy
Mechanical Energy (M.E.) = Kinetic Energy (K.E.) + Potential Energy (P.E.).
Energy is also measured in Joules and erg, In SI and CGS systems respectively.
The Work Energy Theorem states that work done by a force is always equal to change in its Kinetic Energy.
Work done by the gravitational force is called Gravitational Potential Energy.
Work Done = ΔK.E.
W = 1/2 mv²-1/2mu²
W = F•s cos θ
cos 0°*= 1
W = F•s
W = m•a•s
v²-u² = 2as
W = ΔK.E.
W = 1/2 m•(v²-u²) is the Work Energy Theorem
Mathematically, Hooke’s law is expressed as: F ∝ x (displacement from mean position) or F = -kx.
If mass and velocity are given to us in a question, we can derive 2 quantities from this information: linear momentum (p=mv) and kinetic energy (K.E = 1/2mv²).
W = m• |v²/2| is the kinetic energy of a freely falling body.
W = K.E.(f) - K.E(i) is the kinetic energy of a freely falling body.
dW = ma•dx is the differential of work done by an acceleration.
DW = F•dx is the differential of work done by a force.
In the equation, F = - KX, F is the force, x is the extension in length, and k is the spring constant (N/m)
Elastic potential energy in spring is a variableforce (because it’s a restoring force).
a = dv/dt is the differential of acceleration.
Hooke’s law states that the strain of the material is proportional to the applied stress within the elastic limit of that material.
B is at a height H-x (x is the already travelled distance) where K.E.= 1/2mv².
W = 1/2mv² - 1/2mu² is the WorkEnergyTheorem
T.E = K.E + P.E.
C is just before touching the ground (almost at H=0) where K.E.= 1/2mv².
p = √2m•K.E or K.E = p²/2m is the relation between kinetic energy of a freely falling body.