quiz 6 (3/5)

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Created by
jael smith

Cards (5)

  • converting pH, pOH, [H+], and [OH]
    • pH = -log[H+]
    • pOH = -log[OH-]
    • Kw = [H+][OH-]=10^-14 at 25ºC
    • pKw = pH + pOH = 14 at 25ºC
  • converting pKa, pKb, Ka, and Kb
    • pKa = -log(Ka)
    • pKb = -log(Kb)
    • Kw = KaKb = 10^-14 at 25ºC
    • pKw = pKa + pKb = 14 at 25ºC
  • simple acid/base calc: strong
    1. determine if strong or weak
    2. remove spectator ions (strong: H+/OH- remains)
    3. convert to pH
  • simple acid/base calc: weak
    1. remove spectator ions
    2. identify compound (H+/OH-/HA/A-/BH+/B)
    3. no neutralization = solve with appropriate weak acid/base formula
    4. convert to pH, pOH, [h+], [OH-]
  • simple acid/base calc: buffer
    1. remove spectators
    2. identify if strong or weak and its forms (H+/OH-/HA/A-/BH+/B) and recognize compounds conjugates (HA and A-/BH+ and B)
    3. no neutralization = use buffer calculation
    4. convert to pH, pOH, [H+], [OH-]