A mixture contains 20% iron ions by mass. What mass of iron chloride (FeCl2) would you need to provide the iron ions in 50 g of the mixture?
1)Find the mass of iron in the mixture
> The mixture contains 20% iron by mass, so in 50 g there will be 50 x (20 / 100) = 10 g of iron
2) Calculate the % mass of iron in iron chloride
> % mass of iron = 56 / [56 + (2 x 35.5)] x 100 = 44.09...%
3) Calculate the mass of iron chloride that contains 10 g of iron
> Iron chloride contains 44.09% iron by mass, so there will be 10 g of iron in 10 / (44.09... / 100) = 23 g