10.11 Radius and Interval of Convergence of Power Series

Cards (73)

  • What is the general form of a power series?
    n=0cn(xa)n\sum_{n = 0}^{\infty} c_{n}(x - a)^{n}
  • The center of a power series is denoted by the variable a
  • What is the radius of convergence?
    The distance around the center where the series converges
  • The radius of convergence defines the range of x</latex> values for which a power series is guaranteed to converge.
  • The radius of convergence is denoted by the variable R
  • If the radius of convergence R=R =1 1 and the center is a = 2</latex>, what is the range of xx values for convergence?

    1x31 \le x \le 3
  • Match the aspect with its definition:
    Radius of Convergence ↔️ The distance from the center where the series converges
    Center ↔️ The point about which the power series is defined
    Convergence ↔️ The property of the series to approach a finite value
  • The interval of convergence extends beyond the radius of convergence to include the endpoints
  • The interval of convergence can include (aR,a+R)(a - R, a + R), [aR,a+R][a - R, a + R], or (aR,a+R](a - R, a + R] depending on the convergence at the endpoints.
  • What is the condition for convergence in the ratio test?
    \lim_{n \to \infty} \left| \frac{c_{n + 1} (x - a)^{n + 1}}{c_{n} (x - a)^{n}} \right| < 1</latex>
  • The power series n=0(x3)nn!\sum_{n = 0}^{\infty} \frac{(x - 3)^{n}}{n!} has a radius of convergence \infty
  • What does the radius of convergence define?
    The range of xx values for guaranteed convergence
  • What are the coefficients in a power series called?
    Coefficients
  • The center of a power series is denoted by the variable a
  • The radius of convergence is essential for understanding the behavior of a power series.
  • What does the radius of convergence define in a power series?
    The distance from the center where the series converges
  • The interval of convergence includes the endpoints a - R and a+a +R R
  • If both endpoints of the interval of convergence converge, the interval is expressed as [aR,a+R][a - R, a + R].
  • What is the condition for convergence if both endpoints diverge in the interval of convergence?
    (aR,a+R)(a - R, a + R)
  • The ratio test states that a series converges if \lim_{n \to \infty} \left| \frac{c_{n + 1} (x - a)^{n + 1}}{c_{n} (x - a)^{n}} \right| < 1
  • What is the radius of convergence for the power series \sum_{n = 0}^{\infty} \frac{(x - 3)^{n}}{n!}</latex>?
    R=R = \infty
  • Steps to find the radius of convergence using the ratio test
    1️⃣ Apply the ratio test to the power series
    2️⃣ Simplify the expression
    3️⃣ Solve for xa|x - a|
    4️⃣ Set xa<R|x - a| < R to determine the convergence range
  • To find the interval of convergence, after determining the radius of convergence RR, you must test the endpoints
  • The series n=1(1)nn\sum_{n = 1}^{\infty} \frac{( - 1)^{n}}{n} converges by the Alternating Series Test.
  • What does the series n=11n\sum_{n = 1}^{\infty} \frac{1}{n} diverge to?

    Infinity
  • Match the endpoint convergence with the resulting series behavior:
    x=x =aR a - R ↔️ Converges
    x=x =a+ a +R R ↔️ Diverges
  • What must you test after determining the radius of convergence of a power series to find the interval of convergence?
    The endpoints
  • To find the interval of convergence, you must substitute x=x =aR a - R and x=x =a+ a +R R into the power series
  • Steps to find the interval of convergence after determining the radius of convergence.
    1️⃣ Substitute x = a - R</latex> and x=x =a+ a +R R into the power series
    2️⃣ Evaluate each resulting series
    3️⃣ Determine whether each series converges or diverges
    4️⃣ Combine the convergence results with the radius of convergence
  • The radius of convergence determines whether a power series converges or diverges for all xx values.

    False
  • What are the values of aa and RR for the power series \sum_{n = 1}^{\infty} \frac{(x - 2)^{n}}{n}</latex>?

    a=a =2,R= 2, R =1 1
  • For x=x =1 1, the series n=1(1)nn\sum_{n = 1}^{\infty} \frac{( - 1)^{n}}{n} converges by the Alternating Series Test
  • The interval of convergence for the power series n=1(x2)nn\sum_{n = 1}^{\infty} \frac{(x - 2)^{n}}{n} is [1,3)[1, 3).
  • What are two common types of series used to approximate functions?
    Taylor and Maclaurin
  • The Taylor series expands a function f(x)f(x) about a point x=x =a a using its derivatives
  • What is the value of aa in the Maclaurin series?

    a = 0</latex>
  • Steps to approximate f(x)=f(x) =ex e^{x} using a Maclaurin series up to the third term.

    1️⃣ Calculate f(0)f(0)
    2️⃣ Find the first, second, and third derivatives of f(x)f(x)
    3️⃣ Evaluate the derivatives at x=x =0 0
    4️⃣ Substitute the values into the Maclaurin series formula
  • What is the approximation of exe^{x} using a Maclaurin series up to the third term?

    1+1 +x+ x +x22!+ \frac{x^{2}}{2!} +x33! \frac{x^{3}}{3!}
  • The Maclaurin series is a special case of the Taylor series with a=a =0 0.
  • What is the general form of a power series centered ata</latex>?
    n=0cn(xa)n\sum_{n = 0}^{\infty} c_{n}(x - a)^{n}