9.3 Finding Arc Lengths of Curves Given by Parametric Equations

    Cards (38)

    • What is the arc length formula for y=y =x2 x^{2} from x=x =0 0 to x=x =1 1?

      L=L =011+4x2dx \int_{0}^{1} \sqrt{1 + 4x^{2}} \, dx
    • The arc length of y=y =x2 x^{2} from x=x =0 0 to x=x =1 1 is approximately 1.14781.1478
    • The arc length of a curve defined by parametric equations is calculated using the formula L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt</latex>, where [a,b][a, b] is the interval of the parameter t
    • What is the derivative of x=x =3t 3t with respect to tt?

      33
    • Trigonometric substitution is used to solve the integral 029+16t2dt\int_{0}^{2} \sqrt{9 + 16t^{2}} \, dt
    • The arc length formula for parametric equations sums the infinitesimal arc lengths as the parameter tt varies from aa to b
    • What are parametric equations used to define?
      A curve
    • The parametric equations x=x =2t 2t and y=y =t2 t^{2} trace a parabola as tt changes.
    • What does the parameter tt in parametric equations describe?

      How coordinates change
    • The formula for arc length in Cartesian coordinates involves the derivative dydx\frac{dy}{dx}.
    • The arc length formula in Cartesian coordinates is L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} \, dx</latex>, where aa and bb are the limits of integration
    • What is the derivative dydx\frac{dy}{dx} for the function y=y =x2 x^{2}?

      2x2x
    • The arc length formula in parametric form uses the derivatives \frac{dx}{dt}</latex> and dydt\frac{dy}{dt}.
    • The arc length formula in parametric form is L=L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt, where aa and bb are the limits of the parameter
    • What is the derivative dxdt\frac{dx}{dt} for the parametric equationx = t</latex>?

      11
    • Match the parametric equations with their derivatives:
      x=x =3t 3t ↔️ dxdt=\frac{dx}{dt} =3 3
      y=y =2t2 2t^{2} ↔️ dydt=\frac{dy}{dt} =4t 4t
    • The derivative of y=y =x2 x^{2} is 2x
    • What is the first step in calculating the arc length of a curve defined by parametric equations?
      Find the derivatives
    • The arc length of the curve x=x =3t 3t and y=y =2t2 2t^{2} for 0 \le t \le 2</latex> is approximately 10.80310.803
    • What are the parametric equations describing the position of a satellite orbiting Earth?
      x(t)=x(t) =5cos(t) 5\cos(t), y(t)=y(t) =4sin(t) 4\sin(t)
    • To find the total distance a satellite covers in one orbit, you calculate the arc length.
    • The arc length of the satellite's orbit is approximately 28.64</latex> units.
    • Match the parametric equations with their derivatives:
      x=x =2t 2t ↔️ dxdt=\frac{dx}{dt} =2 2
      y=y =3t2 3t^{2} ↔️ dydt=\frac{dy}{dt} =6t 6t
      x=x =t3 t^{3} ↔️ dxdt=\frac{dx}{dt} =3t2 3t^{2}
    • What is the purpose of parametric equations in defining a curve?
      Define coordinates using a parameter
    • The arc length formula in Cartesian coordinates is L=L =ab1+(dydx)2dx \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} \, dx
    • For y=y =x2 x^{2}, the derivative dydx\frac{dy}{dx} is 2x
    • What is the formula for arc length using parametric equations?
      L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt</latex>
    • Steps to calculate arc length using parametric equations
      1️⃣ Find the derivatives dxdt\frac{dx}{dt} and dydt\frac{dy}{dt}
      2️⃣ Substitute into the arc length formula
      3️⃣ Evaluate the integral
    • The arc length formula for parametric equations x=x =f(t) f(t) and y=y =g(t) g(t) over an interval [a,b][a, b] is given by: L
    • The arc length formula sums infinitesimal arc lengths obtained from the derivatives of xx and yy with respect to tt.
    • What are the parametric equations used in the first example to calculate arc length?
      x = t</latex> and y=y =t2 t^{2}
    • The exact arc length of the curve x=x =t t and y=y =t2 t^{2} from t=t =0 0 to t=t =1 1 is approximately 1.1478.
    • What are the parametric equations used in the second example to calculate arc length?
      x=x =cos(t) \cos(t) and y=y =sin(t) \sin(t)
    • The arc length of the curve x=x =cos(t) \cos(t) and y=y =sin(t) \sin(t) from t=t =0 0 to t=t =π \pi is equal to π\pi.
    • The simplified integrand for the AUV problem is: 25+25t2\sqrt{25 + 25t^{2}}
    • What is the approximate arc length traveled by the AUV along its spiral path?
      46.4746.47 units
    • The arc length of the curve x(t)=x(t) =t2 t^{2} and y(t)=y(t) =t3 t^{3} from t=t =0 0 to t=t =1 1 is approximately 1.44.
    • The arc length of the circle defined by x(t)=x(t) =4cos(t) 4\cos(t) and y(t) = 4\sin(t)</latex> for 0t2π0 \le t \le 2\pi is approximately 8π8\pi