What is the arc length formula for y=x2 from x=0 to x=1?
L=∫011+4x2dx
The arc length of y=x2 from x=0 to x=1 is approximately 1.1478
The arc length of a curve defined by parametric equations is calculated using the formula L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt</latex>, where [a,b] is the interval of the parameter t
What is the derivative of x=3t with respect to t?
3
Trigonometric substitution is used to solve the integral ∫029+16t2dt
The arc length formula for parametric equations sums the infinitesimal arc lengths as the parameter t varies from a to b
What are parametric equations used to define?
A curve
The parametric equations x=2t and y=t2 trace a parabola as t changes.
What does the parameter t in parametric equations describe?
How coordinates change
The formula for arc length in Cartesian coordinates involves the derivative dxdy.
The arc length formula in Cartesian coordinates is L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} \, dx</latex>, where a and b are the limits of integration
What is the derivative dxdy for the function y=x2?
2x
The arc length formula in parametric form uses the derivatives \frac{dx}{dt}</latex> and dtdy.
The arc length formula in parametric form is L= \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt, where a and b are the limits of the parameter
What is the derivative dtdx for the parametric equationx = t</latex>?
1
Match the parametric equations with their derivatives:
x=3t ↔️ dtdx=3
y=2t2 ↔️ dtdy=4t
The derivative of y=x2 is 2x
What is the first step in calculating the arc length of a curve defined by parametric equations?
Find the derivatives
The arc length of the curve x=3t and y=2t2 for 0 \le t \le 2</latex> is approximately 10.803
What are the parametric equations describing the position of a satellite orbiting Earth?
x(t)=5cos(t), y(t)=4sin(t)
To find the total distance a satellite covers in one orbit, you calculate the arc length.
The arc length of the satellite's orbit is approximately 28.64</latex> units.
Match the parametric equations with their derivatives:
x=2t ↔️ dtdx=2
y=3t2 ↔️ dtdy=6t
x=t3 ↔️ dtdx=3t2
What is the purpose of parametric equations in defining a curve?
Define coordinates using a parameter
The arc length formula in Cartesian coordinates is L=∫ab1+(dxdy)2dx
For y=x2, the derivative dxdy is 2x
What is the formula for arc length using parametric equations?
L = \int_{a}^{b} \sqrt{\left(\frac{dx}{dt}\right)^{2} + \left(\frac{dy}{dt}\right)^{2}} \, dt</latex>
Steps to calculate arc length using parametric equations
1️⃣ Find the derivatives dtdx and dtdy
2️⃣ Substitute into the arc length formula
3️⃣ Evaluate the integral
The arc length formula for parametric equations x=f(t) and y=g(t) over an interval [a,b] is given by: L
The arc length formula sums infinitesimal arc lengths obtained from the derivatives of x and y with respect to t.
What are the parametric equations used in the first example to calculate arc length?
x = t</latex> and y=t2
The exact arc length of the curve x=t and y=t2 from t=0 to t=1 is approximately 1.1478.
What are the parametric equations used in the second example to calculate arc length?
x=cos(t) and y=sin(t)
The arc length of the curve x=cos(t) and y=sin(t) from t=0 to t=π is equal to π.
The simplified integrand for the AUV problem is: 25+25t2
What is the approximate arc length traveled by the AUV along its spiral path?
46.47 units
The arc length of the curve x(t)=t2 and y(t)=t3 from t=0 to t=1 is approximately 1.44.
The arc length of the circle defined by x(t)=4cos(t) and y(t) = 4\sin(t)</latex> for 0≤t≤2π is approximately 8π