A relative maximum occurs when f(c)≥f(x) for all x near c.
Relative extrema occur at critical points where f′(x)=0 or f′(x) is undefined
Match the characteristic with the type of relative extrema:
f′′(c)<0 ↔️ Relative Maximum
f′′(c)>0 ↔️ Relative Minimum
What does the second derivative represent in calculus?
Rate of change of slope
If f′′(x)>0, the function is concave up.
A point of inflection occurs when f′′(x)=0 and concavity changes.
Match the second derivative sign with the concavity:
f''(x) > 0</latex> ↔️ Concave Up
f′′(x)<0 ↔️ Concave Down
f′′(x)=0 ↔️ Point of Inflection
What does f′′(x)=0 indicate about the concavity of a function?
Potential change in concavity
The first derivative f′(x) determines the concavity
If f′′(x)>0, the function is concave up.
If f′′(x)<0, the function is concave down.
The second derivative is denoted as f′′(x) and is the derivative of the first derivative f′(x) to determine concavity
If f′′(x)=0, it indicates a possible point of inflection.
Steps to find relative extrema using the second derivative test
1️⃣ Find the first derivative f′(x)
2️⃣ Determine critical points by setting f′(x)=0
3️⃣ Find the second derivative f′′(x)
4️⃣ Evaluate f′′(c) for each critical point c
If f′′(c)>0, then f(c) is a relative minimum
If f''(c) = 0</latex>, the second derivative test is inconclusive.
If f′′(c)>0, what is f(c)?
Relative minimum
If f''(c) <0</latex>, then f(c) is a relative maximum.
What happens if f′′(c)=0?
Test is inconclusive
Steps to find relative extrema using the second derivative test
1️⃣ Find the first derivative f′(x)
2️⃣ Determine the critical points by setting f′(x)=0
3️⃣ Find the second derivative f′′(x)
4️⃣ Evaluate f′′(c) for each critical point c
If f′′(c)>0, then f(c) is a relative minimum.
For f(x)=x3−6x2+5, what is the value of f′′(0)?
-12
For f(x)=x3−6x2+5, f''(4) =12</latex> indicates a relative minimum
What are relative extrema in calculus?
Local high and low points
Define a relative maximum.
f(c)≥f(x) for all x near c
What does the second derivative represent?
Rate of change of slope
If f′′(x)>0, the function is concave up.
If f''(x) < 0</latex>, the function is concave down
What does f′′(x)=0 indicate?
Potential point of inflection
For f(x) = x^{3}</latex>, f′(x)=3x2, and f′′(x)=6x, is the function concave up for x>0?
Yes
What is one condition for using the second derivative test?
Function twice differentiable
A critical point c for the second derivative test requires f'(c) = 0
If f′′(c)<0, what is the result of the second derivative test?
Relative maximum
If f′′(c)>0, what is the result of the second derivative test?
Relative minimum
Steps to apply the second derivative test to find relative extrema:
1️⃣ Find the first derivative f′(x) and determine the critical points by setting f′(x)=0
2️⃣ Find the second derivative f′′(x)
3️⃣ Evaluate f′′(c) for each critical point c
Match the sign of f′′(c) with its result in the second derivative test:
Positive ↔️ Relative minimum at f(c)
Negative ↔️ Relative maximum at f(c)
Zero ↔️ Test is inconclusive
A positive value of f′′(c) indicates a relative minimum at f(c)
If f′′(c)=0, the second derivative test is inconclusive
Interpreting the results of the second derivative test involves analyzing the sign of f′′(c) at critical points to determine if the point is a relative maximum, relative minimum, or inconclusive