1.8 Determining Limits Using the Squeeze Theorem

Cards (43)

  • The Squeeze Theorem states that if f(x)g(x)h(x)f(x) ≤ g(x) ≤ h(x) and limxcf(x)=\lim_{x \to c} f(x) =L L and limxch(x)=\lim_{x \to c} h(x) =L L, then limxcg(x)=\lim_{x \to c} g(x) =L L. This is useful when direct substitution
  • One step in using the Squeeze Theorem is to identify bounding functions f(x)f(x) and h(x)h(x) such that f(x) ≤ g(x) ≤ h(x)</latex>.
  • What is the definition of the lower bound function f(x)f(x) in the Squeeze Theorem?

    f(x)g(x)f(x) ≤ g(x)
  • In the example limx0x2sin(1x)\lim_{x \to 0} x^{2} \sin\left(\frac{1}{x}\right), the bounding functions are x2- x^{2} and x2x^{2} because 1sin(1x)1- 1 ≤ \sin\left(\frac{1}{x}\right) ≤ 1 implies - x^{2} ≤ x^{2} \sin\left(\frac{1}{x}\right) ≤ x^{2}</latex>.
  • What are the bounding functions for limx0xcos(1x)\lim_{x \to 0} x \cos\left(\frac{1}{x}\right)?

    xxcos(1x)x- |x| ≤ x \cos\left(\frac{1}{x}\right) ≤ |x|
  • Steps to use the Squeeze Theorem
    1️⃣ Find bounding functions f(x)f(x) and h(x)h(x) such that f(x)g(x)h(x)f(x) ≤ g(x) ≤ h(x).
    2️⃣ Evaluate limxcf(x)\lim_{x \to c} f(x) and limxch(x)\lim_{x \to c} h(x).
    3️⃣ Confirm that limxcf(x)=\lim_{x \to c} f(x) =limxch(x)= \lim_{x \to c} h(x) =L L.
    4️⃣ Conclude that limxcg(x)=\lim_{x \to c} g(x) =L L.
  • The Squeeze Theorem is also known as the Pinching Theorem.
  • In the example limx0x2sin(1x)\lim_{x \to 0} x^{2} \sin\left(\frac{1}{x}\right), the bounding functions are x2- x^{2} and x2x^{2} because 1sin(1x)1- 1 ≤ \sin\left(\frac{1}{x}\right) ≤ 1 implies - x^{2} ≤ x^{2} \sin\left(\frac{1}{x}\right) ≤ x^{2}</latex>.
  • What are the bounding functions for limx0xcos(1x)\lim_{x \to 0} x \cos\left(\frac{1}{x}\right)?

    xxcos(1x)x- |x| ≤ x \cos\left(\frac{1}{x}\right) ≤ |x|
  • One condition for using the Squeeze Theorem is that the limits of the bounding functions must be equal.
  • The first step in using the Squeeze Theorem is to identify bounding functions
  • The Squeeze Theorem requires that the limits of the bounding functions are equal.
  • Steps to find bounding functions for the Squeeze Theorem
    1️⃣ Analyze the target function g(x)g(x)
    2️⃣ Use trigonometric bounds such as 1sin(x)1- 1 ≤ \sin(x) ≤ 1 or 1cos(x)1- 1 ≤ \cos(x) ≤ 1
    3️⃣ Apply absolute values if needed
  • A function f(x)f(x) is a lower bound of g(x)g(x) if f(x)g(x)f(x) ≤ g(x) for all xx near cc.
  • What is the first step in evaluating the limits of bounding functions in the Squeeze Theorem?
    Determine the limit expression
  • Ensuring that the limits of the bounding functions are equal is necessary to apply the Squeeze Theorem.
  • What is another name for the Squeeze Theorem?
    Pinching Theorem
  • The Squeeze Theorem can be used when direct substitution is not possible.
  • The Squeeze Theorem requires identifying bounding functions
  • The Squeeze Theorem is also known as the Pinching Theorem.
  • The Squeeze Theorem requires that the target function is bounded between two other functions near a point cc.
  • To apply the Squeeze Theorem, you must identify two bounding functions.
  • Steps to apply the Squeeze Theorem
    1️⃣ Identify bounding functions f(x)f(x) and h(x)h(x) such that f(x)g(x)h(x)f(x) ≤ g(x) ≤ h(x) for xx near cc.
    2️⃣ Show that limxcf(x)=\lim_{x \to c} f(x) =L L and limxch(x)=\lim_{x \to c} h(x) =L L.
    3️⃣ Conclude that limxcg(x)=\lim_{x \to c} g(x) =L L.
  • The limit of x2sin(1x)x^{2} \sin\left(\frac{1}{x}\right) as x0x \to 0 is 0.
  • The limit of xcos(1x)x \cos\left(\frac{1}{x}\right) as x0x \to 0 is 0.
  • The trigonometric bounds 1sin(x)1- 1 ≤ \sin(x) ≤ 1 and 1cos(x)1- 1 ≤ \cos(x) ≤ 1 are useful for finding bounding functions.
  • Trigonometric bounds can be used to find bounding functions when dealing with sine or cosine functions.
  • What is a lower bound of a function g(x)g(x)?

    f(x)g(x)f(x) ≤ g(x)
  • Steps to find bounding functions for a given function g(x)g(x)
    1️⃣ Analyze the target function g(x)g(x) to identify potential bounding expressions
    2️⃣ Use trigonometric bounds such as 1sin(x)1- 1 ≤ \sin(x) ≤ 1 and 1cos(x)1- 1 ≤ \cos(x) ≤ 1
    3️⃣ Apply absolute values to ensure non-negative values if needed
  • The trigonometric bound 1cos(x)1- 1 ≤ \cos(x) ≤ 1 is true for all xx.
  • For g(x)=g(x) =x2sin(1x) x^{2} \sin\left(\frac{1}{x}\right), what is the lower bound f(x)f(x)?

    x2- x^{2}
  • Match the function with its definition or bound:
    Target function g(x)g(x) ↔️ g(x)g(x)
    Lower bound f(x)f(x) ↔️ f(x)g(x)f(x) ≤ g(x)
    Upper bound h(x)h(x) ↔️ g(x)h(x)g(x) ≤ h(x)
  • What condition must f(x)f(x) satisfy to be a lower bound of g(x)g(x)?

    f(x)g(x)f(x) ≤ g(x)
  • Steps to find bounding functions for a given function g(x)g(x)
    1️⃣ Analyze the target function g(x)g(x) to identify potential bounding expressions
    2️⃣ Use trigonometric bounds such as 1sin(x)1- 1 ≤ \sin(x) ≤ 1 and 1cos(x)1- 1 ≤ \cos(x) ≤ 1
    3️⃣ Apply absolute values to ensure non-negative values if needed
  • For g(x)=g(x) =x2sin(1x) x^{2} \sin\left(\frac{1}{x}\right), what is the upper bound h(x)h(x)?

    x2x^{2}
  • Match the function with its definition or bound:
    Target function g(x)g(x) ↔️ g(x)g(x)
    Lower bound f(x)f(x) ↔️ f(x)g(x)f(x) ≤ g(x)
    Upper bound h(x)h(x) ↔️ g(x)h(x)g(x) ≤ h(x)
  • What is the first step in evaluating the limits of bounding functions when using the Squeeze Theorem?
    Determine the limit expression
  • Steps to evaluate the limits of bounding functions for the Squeeze Theorem
    1️⃣ Determine the limit expression
    2️⃣ Substitute x=x =c c
    3️⃣ Simplify
    4️⃣ Ensure equal limits
  • If \lim_{x \to 1} (2x + 1) = 3</latex> and limx1(3x1)=\lim_{x \to 1} (3x - 1) =2 2, the Squeeze Theorem can be applied.

    False
  • For the Squeeze Theorem to be applicable, the bounding functions must have the same limit