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Unit 3: Particle Model of Matter
3.2 Changes of State
3.2.3 Specific Latent Heat
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What is specific latent heat defined as?
Energy to change state
Specific latent heat is measured in joules per
kilogram
The formula for specific latent heat is
E
=
E =
E
=
m
L
mL
m
L
What does
E
E
E
represent in the formula for specific latent heat?
Energy required
Match the type of latent heat with its value and process:
Fusion ↔️
3.34
×
1
0
5
3.34 × 10^{5}
3.34
×
1
0
5
J/kg, Solid to Liquid
Vaporization ↔️
2.26
×
1
0
6
2.26 × 10^{6}
2.26
×
1
0
6
J/kg, Liquid to Gas
Steps involved in calculating the energy required for latent heat of fusion
1️⃣ Determine the mass of the substance
2️⃣ Identify the specific latent heat of fusion
3️⃣ Use the formula
E
=
E =
E
=
m
L
f
mL_{f}
m
L
f
4️⃣ Calculate the energy required
What state change is associated with latent heat of fusion?
Solid to liquid
Latent heat of vaporization is measured in joules per
kilogram
.
The energy required to boil 1 kg of water with a specific latent heat of vaporization of
2.26
×
1
0
6
2.26 × 10^{6}
2.26
×
1
0
6
J/kg is
2.26
×
1
0
6
2.26 × 10^{6}
2.26
×
1
0
6
J
What is the latent heat of fusion defined as?
Energy to change solid to liquid
What does the variable
E
E
E
represent in the formula for latent heat of fusion?
Energy required
The specific latent heat of fusion is measured in units of
J/kg
How much energy is required to melt 3 kg of ice if its specific latent heat of fusion is
3.34
×
1
0
5
J
/
k
g
3.34 × 10^{5} J / kg
3.34
×
1
0
5
J
/
k
g
?
1.002
×
1
0
6
J
1.002 × 10^{6} J
1.002
×
1
0
6
J
The latent heat of fusion is specific to each
substance
.
The latent heat of vaporization is the energy needed to change 1 kg of a substance from a
liquid
to a gas without changing its temperature.
What formula is used to calculate the energy required for vaporization?
E
=
E =
E
=
m
L
v
mL_{v}
m
L
v
The specific latent heat of vaporization is denoted by
L_{v}
The specific latent heat of vaporization for water is 2.26 × 10^{6} J /
kg
</latex>.
How much energy is required to vaporize 1 kg of water if its specific latent heat of vaporization is
2.26
×
1
0
6
J
/
k
g
2.26 × 10^{6} J / kg
2.26
×
1
0
6
J
/
k
g
?
2.26
×
1
0
6
J
2.26 × 10^{6} J
2.26
×
1
0
6
J
The latent heat of vaporization is measured in units of
J/kg
What is specific latent heat defined as?
Energy to change state of 1 kg
What is the formula to calculate the energy required using specific latent heat?
E
=
E =
E
=
m
L
mL
m
L
Specific latent heat is denoted by the variable
L
L
L
.
Specific latent heat is measured in units of
J/kg
How much energy is needed to melt 2 kg of ice if its specific latent heat of fusion is
3.34
×
1
0
5
J
/
k
g
3.34 × 10^{5} J / kg
3.34
×
1
0
5
J
/
k
g
?
6.68
×
1
0
5
J
6.68 × 10^{5} J
6.68
×
1
0
5
J
To solve problems involving specific latent heat, the formula used is
E = mL
How much energy is needed to melt 5 kg of ice if its specific latent heat of fusion is
3.34
×
1
0
5
J
/
k
g
3.34 × 10^{5} J / kg
3.34
×
1
0
5
J
/
k
g
?
1.67
×
1
0
6
J
1.67 × 10^{6} J
1.67
×
1
0
6
J
What is the latent heat of fusion defined as?
Energy needed to melt 1 kg
The formula to calculate the energy required for melting is
mL_{f}
What are the units of specific latent heat of fusion?
J/kg
The specific latent heat of fusion of ice is approximately
3.34
×
1
0
5
J
/
k
g
3.34 × 10^{5} J / kg
3.34
×
1
0
5
J
/
k
g
.
The formula for latent heat of fusion is
E = mL_{f}
What is the latent heat of vaporization defined as?
Energy needed to vaporize 1 kg
The formula to calculate the energy required for vaporization is
mL_{v}
What is the specific latent heat of vaporization of water?
2.26
×
1
0
6
J
/
k
g
2.26 × 10^{6} J / kg
2.26
×
1
0
6
J
/
k
g
The latent heat of fusion for water is less than its
latent heat of vaporization
.
Match the term with its definition:
Specific Latent Heat ↔️ Energy to change 1 kg without changing temperature
Latent Heat of Fusion ↔️ Energy to change solid to liquid
Latent Heat of Vaporization ↔️ Energy to change liquid to gas
What is the formula to calculate the energy required using specific latent heat?
E
=
E =
E
=
m
L
mL
m
L
To melt 2 kg of ice with
L
=
L =
L
=
3.34
×
1
0
5
J
/
k
g
3.34 × 10^{5} J / kg
3.34
×
1
0
5
J
/
k
g
, the energy needed is
6.68
×
1
0
5
J
6.68 × 10^{5} J
6.68
×
1
0
5
J
The variable
L
L
L
in the specific latent heat formula represents energy required.
False
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