2.2 Work, Energy, and Power

    Cards (157)

    • What is work done measured in?
      Joules
    • Work done is a scalar quantity
    • When the force is constant and parallel to the displacement, the formula for work done is W = Fd
    • What formula is used to calculate work done by a variable force?
      W=W =abFds \int_{a}^{b} F \cdot ds
    • The formula W=W =Fd Fd is used for work done by a variable force

      False
    • Match the force type with its work done calculation:
      Constant Force ↔️ W=W =Fd Fd
      Variable Force ↔️ W=W =abFds \int_{a}^{b} F \cdot ds
    • Potential energy is the stored energy an object has due to its position
    • What is the formula for gravitational potential energy?
      PE=PE =mgh mgh
    • Elastic potential energy is calculated using the formula PE=PE =12kx2 \frac{1}{2} kx^{2}
    • What is the formula for kinetic energy?
      KE = \frac{1}{2} mv^{2}</latex>
    • Kinetic energy is the energy of motion
    • Match the concept with its definition and formula:
      Power ↔️ Rate at which work is done; P=P =Wt \frac{W}{t}
      Work Done ↔️ Energy transferred by a force; W=W =Fd Fd
    • Power is measured in units called Watts
    • What is the formula for power?
      P=P =Wt \frac{W}{t}
    • Power is a scalar quantity
    • Arrange the following in the correct order for calculating work done by a variable force:
      1️⃣ Identify the force function
      2️⃣ Set the limits of integration
      3️⃣ Perform the integration
    • What is the formula for work done when a constant force is applied?
      W=W =Fd Fd
    • In the formula for work done, dd represents the distance
    • The work done by a constant force is calculated using the formula W = Fd</latex>.
    • Match the type of potential energy with its formula and key variables:
      Gravitational Potential Energy ↔️ PE=PE =mgh mgh ||| Mass (mm), Gravitational Acceleration (gg), Height (hh)
      Elastic Potential Energy ↔️ PE=PE =12kx2 \frac{1}{2} kx^{2} ||| Spring Constant (kk), Displacement (xx)
      Electric Potential Energy ↔️ PE=PE =qV qV ||| Charge (qq), Electric Potential (VV)
    • The formula for gravitational potential energy is PE=PE =mgh mgh
    • What is kinetic energy measured in?
      Joules (J)
    • The formula for kinetic energy is KE = \frac{1}{2} mv^{2}</latex>.
    • In the kinetic energy formula, vv represents the object's velocity
    • What is the formula for power?
      P=P =Wt \frac{W}{t}
    • Match the concept with its definition and formula:
      Power ↔️ Rate at which work is done ||| P=P =Wt \frac{W}{t}
      Work Done ↔️ Energy transferred by a force ||| W=W =Fd Fd
      Energy ↔️ Capacity to do work ||| Varies depending on the type
    • Power is measured in Watts
    • What does the Work-Energy Principle state?
      Net work equals change in KE
    • The Work-Energy Principle is expressed as Wnet=W_{net} =ΔKE \Delta KE.
    • Steps to solve the example problem using the Work-Energy Principle
      1️⃣ Calculate the work done: W=W =Fd= Fd =200J 200 J
      2️⃣ Use the work-energy principle: ΔKE=\Delta KE =W= W =200J 200 J
      3️⃣ Calculate the final kinetic energy: KEf=KE_{f} =210J 210 J
      4️⃣ Find the final speed: vf9.17m/sv_{f} \approx 9.17 m / s
    • What is the formula for work done by a force moving an object?
      W=W =Fd Fd
    • The kinetic energy of an object is measured in Joules
    • What does the Work-Energy Principle state?
      Work equals change in KE
    • The Work-Energy Principle can be expressed as W = \Delta KE = KE_{f} - KE_{i}</latex>, where KEfKE_{f} and KEiKE_{i} are the final and initial kinetic energies
    • In the example problem, what is the work done on the 5 kg block?
      200 J
    • Steps to solve the example problem using the Work-Energy Principle:
      1️⃣ Calculate the work done: W = Fd</latex>
      2️⃣ Use the Work-Energy Principle: ΔKE=\Delta KE =W W
      3️⃣ Calculate the final kinetic energy: KEf=KE_{f} =KEi+ KE_{i} +ΔKE \Delta KE
      4️⃣ Find the final speed: vf=v_{f} =2×KEfm \sqrt{\frac{2 \times KE_{f}}{m}}
    • The final speed of the block in the example problem is approximately 9.17 m/s.
    • Match the concept with its definition, formula, and unit:
      Work ↔️ Energy transferred by a force moving an object ||| W=W =Fd Fd ||| Joules (J)
      Kinetic Energy ↔️ Energy possessed by an object due to its motion ||| KE=KE =12mv2 \frac{1}{2}mv^{2} ||| Joules (J)
    • What is the definition of work done?
      Energy transferred by a force
    • The formula for work done by a constant force is W=W =Fd Fd, while for a variable force it is W = \int_{a}^{b} F \cdot ds</latex>.distance
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