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4. Calculus
4.2 Integration
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Cards (94)
What is the reverse process of differentiation called?
Integration
The power rule for integration states that \int x^{n} dx = \frac{x^{n + 1}}{n + 1} + C</latex>, where
n
≠
−
1
n \neq - 1
n
=
−
1
and
C
C
C
is the constant of integration
The constant of integration,
C
C
C
, is necessary in indefinite integrals.
What is the result of integrating
x
3
x^{3}
x
3
with respect to
x
x
x
?
x
4
4
+
\frac{x^{4}}{4} +
4
x
4
+
C
C
C
The constant rule for integration states that
∫
k
d
x
=
\int k dx =
∫
k
d
x
=
k
x
+
kx +
k
x
+
C
C
C
, where
k
k
k
is a constant
What is the result of integrating
5
5
5
with respect to
x
x
x
?
5
x
+
5x +
5
x
+
C
C
C
The constant multiple rule states that
∫
k
f
(
x
)
d
x
=
\int k f(x) dx =
∫
k
f
(
x
)
d
x
=
k
∫
f
(
x
)
d
x
k \int f(x) dx
k
∫
f
(
x
)
d
x
, where
k
k
k
is a constant.
What is the result of integrating
2
x
2x
2
x
with respect to
x
x
x
?
x
2
+
x^{2} +
x
2
+
C
C
C
The sum/difference rule for integration states that
∫
[
f
(
x
)
±
g
(
x
)
]
d
x
=
\int [f(x) \pm g(x)] dx =
∫
[
f
(
x
)
±
g
(
x
)]
d
x
=
∫
f
(
x
)
d
x
±
∫
g
(
x
)
d
x
\int f(x) dx \pm \int g(x) dx
∫
f
(
x
)
d
x
±
∫
g
(
x
)
d
x
, which allows you to split the integral into separate terms
What is the result of integrating
x
2
+
x^{2} +
x
2
+
3
x
3x
3
x
with respect to
x
x
x
?
x
3
3
+
\frac{x^{3}}{3} +
3
x
3
+
3
x
2
2
+
\frac{3x^{2}}{2} +
2
3
x
2
+
C
C
C
A definite integral represents the area under a curve between two
limits
.
The fundamental theorem of calculus states that \int_{a}^{b} f(x) dx = F(b) - F(a)</latex>, where
F
(
x
)
F(x)
F
(
x
)
is the antiderivative of
f
(
x
)
f(x)
f
(
x
)
.
What is the value of
∫
1
3
(
2
x
+
1
)
d
x
\int_{1}^{3} (2x + 1) dx
∫
1
3
(
2
x
+
1
)
d
x
?
10
10
10
Steps to evaluate a definite integral using the fundamental theorem of calculus
1️⃣ Find the antiderivative of the function
2️⃣ Evaluate the antiderivative at the upper and lower limits
3️⃣ Subtract the lower limit value from the upper limit value
What should you always include when finding an indefinite integral?
+
+
+
C
C
C
A definite integral has numerical limits, while an
indefinite integral
does not.
Integration by substitution is a technique used to simplify integrals by changing the variable of
integration
In integration by substitution, what do you typically substitute
u
u
u
for?
g
(
x
)
g(x)
g
(
x
)
Steps to perform integration by substitution
1️⃣ Identify a suitable substitution
u
=
u =
u
=
g
(
x
)
g(x)
g
(
x
)
2️⃣ Compute
d
u
=
du =
d
u
=
g
′
(
x
)
d
x
g'(x) dx
g
′
(
x
)
d
x
3️⃣ Rewrite the integral in terms of
u
u
u
4️⃣ Evaluate the new integral
5️⃣ Substitute back to express the result in terms of
x
x
x
Integration by substitution simplifies integrals by changing the variable of
integration
Integration by substitution is useful when the integrand contains a
composite function
.
Steps to integrate by substitution
1️⃣ Identify a suitable substitution
u
=
u =
u
=
g
(
x
)
g(x)
g
(
x
)
2️⃣ Compute the derivative
d
u
=
du =
d
u
=
g
′
(
x
)
d
x
g'(x) dx
g
′
(
x
)
d
x
3️⃣ Express the integral in terms of
u
u
u
4️⃣ Evaluate the new integral
5️⃣ Substitute back to express the result in terms of
x
x
x
The derivative
g
′
(
x
)
g'(x)
g
′
(
x
)
must be present in the integrand for integration by substitution to work.
Match each step of integration by substitution with its description:
Choose a substitution
u
=
u =
u
=
g
(
x
)
g(x)
g
(
x
)
↔️ Identify a composite function
Calculate
d
u
=
du =
d
u
=
g
′
(
x
)
d
x
g'(x) dx
g
′
(
x
)
d
x
↔️ Compute the derivative
Rewrite integral in terms of
u
u
u
↔️ Change the variable
Integrate with respect to
u
u
u
↔️ Evaluate the new integral
Evaluate
∫
2
x
(
x
2
+
\int 2x(x^{2} +
∫
2
x
(
x
2
+
3
)
4
d
x
3)^{4} dx
3
)
4
d
x
using integration by substitution
Steps to evaluate \int 2x(x^{2} + 3)^{4} dx</latex> using integration by substitution
1️⃣ Let
u
=
u =
u
=
x
2
+
x^{2} +
x
2
+
3
3
3
2️⃣
d
u
=
du =
d
u
=
2
x
d
x
2x dx
2
x
d
x
3️⃣ Rewrite the integral:
∫
u
4
d
u
\int u^{4} du
∫
u
4
d
u
4️⃣ Integrate:
u
5
5
+
\frac{u^{5}}{5} +
5
u
5
+
C
C
C
5️⃣ Substitute back:
\frac{(x^{2} +
3)^{5}}{5} +
C
C
C
Integration by substitution simplifies complex
integrals
The formula for integration by parts is
∫
u
d
v
=
\int u dv =
∫
u
d
v
=
u
v
−
∫
v
d
u
uv - \int v du
uv
−
∫
v
d
u
, where
u
u
u
and
d
v
dv
d
v
are parts of the original integral
Steps to apply integration by parts
1️⃣ Identify
u
u
u
and
d
v
dv
d
v
using LIATE
2️⃣ Calculate
d
u
du
d
u
and
v
v
v
3️⃣ Apply the formula
∫
u
d
v
=
\int u dv =
∫
u
d
v
=
u
v
−
∫
v
d
u
uv - \int v du
uv
−
∫
v
d
u
4️⃣ Evaluate the new integral
5️⃣ Simplify
Match each step of integration by parts with its description:
Identify
u
u
u
and
d
v
dv
d
v
↔️ Use LIATE to choose
Calculate
d
u
du
d
u
and
v
v
v
↔️ Compute the derivatives and integrals
Apply the formula ↔️ Rewrite the integral
Evaluate the new integral ↔️ Solve the remaining integral
Integration by parts is used for products of
functions
When using
integration by parts
, chooseu</latex> to simplify when differentiated.
Match each trigonometric function with its integral:
sin
x
\sin x
sin
x
↔️
−
cos
x
+
- \cos x +
−
cos
x
+
C
C
C
cos
x
\cos x
cos
x
↔️
sin
x
+
\sin x +
sin
x
+
C
C
C
sec
2
x
\sec^{2} x
sec
2
x
↔️
tan
x
+
\tan x +
tan
x
+
C
C
C
tan
x
\tan x
tan
x
↔️
−
ln
∣
cos
x
∣
+
- \ln |\cos x| +
−
ln
∣
cos
x
∣
+
C
C
C
The power rule for integration states that
∫
x
n
d
x
=
\int x^{n} dx =
∫
x
n
d
x
=
x
n
+
1
n
+
1
+
\frac{x^{n + 1}}{n + 1} +
n
+
1
x
n
+
1
+
C
C
C
, where
n
≠
−
1
n \neq - 1
n
=
−
1
and
C
C
C
is the constant of integration
The integral of a constant
k
k
k
is
k
x
+
kx +
k
x
+
C
C
C
.
The constant multiple rule allows you to move a constant outside the
integral
.
What is integration the reverse process of?
Differentiation
∫
k
d
x
=
\int k dx =
∫
k
d
x
=
k
x
+
kx +
k
x
+
C
C
C
, where
k
k
k
is a constant.
∫
k
f
(
x
)
d
x
=
\int k f(x) dx =
∫
k
f
(
x
)
d
x
=
k
∫
f
(
x
)
d
x
k \int f(x) dx
k
∫
f
(
x
)
d
x
, where
k
k
k
is a constant</latex>
∫
[
f
(
x
)
±
g
(
x
)
]
d
x
=
\int [f(x) \pm g(x)] dx =
∫
[
f
(
x
)
±
g
(
x
)]
d
x
=
∫
f
(
x
)
d
x
±
∫
g
(
x
)
d
x
\int f(x) dx \pm \int g(x) dx
∫
f
(
x
)
d
x
±
∫
g
(
x
)
d
x
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