halogens

Cards (80)

  • what is the test for chlorine / bromine
    turns damp blue litmus paper red then bleaches it white
    Br slower than Cl
    Cl2 (g) + H2O (l) -> HCl (aq) + HClO (aq)
    2HClO (aq) -> HCl (aq) + O2(g)
    type of reactions = disproportionation
  • what is the test for iodine
    turns starch solution or starch paper colourless / white to blue - black
  • what is the test for chlorine using a displacement reaction
    bubble chlorine gas though colourless potassium bromide solution and the bromine is liberated
    Cl2 (g) + KBr (aq) -> KCl (aq) + Br2 (aq)
    what colour is the Br2 = orange / brown
  • what is added to distinguish between the aqueous halogens produced during displacement reactions
    hexane
    colour of bromine = brown
  • what is the test for bromine using a displacement reaction
    add bromine to water, then add a little dilute sodium hydroxide solution
    the orange aqueous solution of bromine becomes colourless
    Br2 (g) + 2KI (aq) -> KBr (aq) + I2 (aq)
    what colour is the iodine = darker brown
    addition of hexane - 2 layers form with iodine forming a purple upper layer and the lower aqueous layer turns orange (less bromine)
  • atomic radius vs ionic radius in Chlorine
    ionic radius is double the atomic radius
  • Fluorine (F2)
    appearance = yellow gas
    ion = flouride (F-)
    in water = n/a
    in hexane = n/a
  • Chlorine (Cl2)
    appearance = yellow - green gas
    ion = Chloride (Cl-)
    in hexane = colourless solution
    in water = pale green solution
  • Bromine (Br2)
    appearance = red - brown liquid
    ion = Bromide (Br-)
    in hexane = orange solution
    in water = orange solution
  • Iodine (I2)
    appearance = grey - black solid
    ion = Iodide (I-)
    in hexane = yellow or brown solution
    in water = purple solution
  • solubility of halogens in hexane and water
    "like dissolves like"
    halogen, although soluble in polar water, prefer non polar solvents like hexane
    when non polar molecules like the halogens dissolve in hexane
    much less energy is required to disrupt the weaker vdW forces between molecules
    in the solvent hexane and form a solution
    in water, both the stronger hydrogen bonds and vdW in water need disrupted
    halogens cannot hydrogen bond with water
  • state and explain the trend in bond enthalpy down group 7
    deceases from Cl2 to I2
    as the atomic radius increases
    the shared pair of e- are further from the attraction of the nucleus
    resulting in a weaker bond
    therefore reduces, as it requires less energy to break
    F2 is the exception, as the atomic radius is so small
    that the lone pair of e- cause repulsion
    and weaken the bond
  • state and explain the trend in reactivity down group 7
    decreases
    as atomic radius and shielding increases
    so the outer shell e- is further from the attraction of the nucleus
    therefore the incoming e- is less attracted
  • state and explain the trend in the ability of group 7 to behave as oxdising agents
    oxidising agents are e- acceptors
    oxidising power decreases down group 7
    as atomic radius increases
    the outer shell e- is further from the attraction of the nucleus
    therefore the incoming e- is less attracted
  • F2 reaction with water
    reacts violently
    producing hydrofloric acid and oxygen
    2F2 + 2H2O -> 4HF + O2
  • Cl2 reaction with water (~ means reversible reaction)
    Cl2 + H2O ~ HCl + HClO
    what is HClO = chlorine water
    Cl2 + H2O ~ 2H+ + Cl- + ClO-
  • Br2 reaction with water (~ means reversible reaction)
    Br2 + H2O -> HBr + HBrO
    Br2 + H2O ~ 2H+ + Br- + BrO-
  • I2 reaction with water
    doesnt react with water
    sparingly soluble in water
  • why do halogens not exist naturally in their elemental form
    they are so reactive
  • Cl2 + Br- ->
    orange solution of Br2
  • Cl2 + I- ->
    black precipitate in a brown solution
  • Br2 + I- ->
    black precipitate in a brown solution
  • what is the displacement rule
    a more reactive halogen will oxidise a less reactive halide form a solution of its compound
  • write the equation and ionic equation for chlorine + potassium bromide -> potassium chloride + bromide
    Cl2 (aq) + 2KBr (aq) -> 2KCl (aq) + Br2 (aq)
    Cl2 (aq) + 2Br- (aq) -> 2Cl- (aq) + Br2 (aq)
    reaction name = extraction of bromine from seawater
  • write the equation and ionic equation for chlorine + potassium iodide -> potassium chloride + iodine
    Cl2 (aq) + 2KI (aq) -> 2KCl (aq) + I2 (aq)
    Cl2 (aq) + 2I- (aq) -> 2Cl- (aq) + I2 (aq)
  • write the equation and ionic equation for potassium iodide + bromine -> potassium bromide + iodine
    Br2 (aq) + 2KI (aq) -> 2KBr (aq) + I2 (aq)
    Br2 (aq) + 2I- (aq) -> 2Br- (aq) + I2 (aq)
    what colour is the bromine = orange
    what colour is the iodine = darker brown
    what colour is the iodine in hexane = purple upper layer
  • explain the trend of displacement reactions in redox terms
    fluorine is the most reactive
    smallest atomic radius
    therefore attracts electrons into a low energy shell
    close to nucleus with little shielding
  • explain displacement in terms of oxidising agents
    a more powerful oxidising halogen will displace a less powerful oxidising halogen, from a solution of its salt
  • state and explain the trend of oxidising power of halogens down the group
    oxidising power decreases down the group
    atomic radius and shielding increases
    outer shell is further from the attraction of the nucleus
    therefore the incoming electron into the outer shell
    is less easily attracted
    and oxidising power decreases
    F > Cl > Br > I
  • bromine is a more powerful oxidising agent than iodine, therefore it oxidises iodide ions. explain why
    chlorine has a smaller atomic radius
    with less shielding
    therefore the outer shell electron is closer to the attraction of the nucleus
    this results in an incoming electron being more easily attracted into the outer shell of Cl2
    than the larger Br2
  • write the equation for the reaction of chlorine with COLD DILUTE sodium hydroxide
    2NaOH + Cl2 -> NaClO + NaCl + H2O
    colour change = green to colouress
  • write the ionic equation for the reaction of COLD DILUTE sodium hydroxide and chlorine
    2OH- (aq) + Cl2 (aq) -> ClO- (aq) + Cl- (aq) + H2O (l)
  • write the equation for the reaction of chlorine with HOT CONCENTRATED sodium hydroxide
    3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O
    colour change = green to colourless
  • write the ionic equation for HOT CONCENTRATED sodium hydroxide and chlorine
    3Cl2 (aq) + 6OH- (aq) -> 5Cl- (aq) + ClO3- (aq) + H2O (l)
  • what is the systematic name for NaClO
    sodium chlorate (I)
  • what is the systematic name for NaClO3
    sodium chlorate (V)
  • what is the name for Cl-
    chloride
    oxidation number = -1
  • what is the name for Cl2
    chlorine
    oxidation number = 0
  • what is the name for chlorate
    chlorate (I)
    oxidation number = +1
  • what is the name for ClO3-
    chlorate (V)
    oxidation number = +5