AP Calculus AB

Cards (96)

  • Average Rate of Change of f(x) on [a,b]
  • Instantaneous Rate of Change at x=a
  • If f(x) is increasing, then f'(x) is?
    f'(x) = Positive
  • If f(x) is decreasing, then f'(x) is?
    f'(x) = Negative
  • If f(x) is concave up, then f''(x) is?
    f''(x) = positive
  • If f(x) is concave down, then f''(x) is?
    f''(x) = negative
  • If f'(x) is increasing, then f''(x) is?
    f''(x) = positive
  • If f'(x) is decreasing, then f''(x) is?
    f''(x) = negative
  • Equation for the line tangent to f(x) at x=a

    y-f(a)=f'(a)(x-a)
  • Slope of the line tangent to f(x) at x=a
    f'(a)
  • A function is continuous if and only if;
  • If a function is "differentiable" then,
    It is also continuous
  • Derivative of e^x
  • Derivative of a^x
  • Derivative of sinx
  • Derivative of cosx
  • Derivative of tanx
  • Derivative of lnx
  • Derivative of arcsin(x)
  • Derivative of arctan(x)
  • Derivative of square root of x
  • Derivative of x^n
  • Derivative of f(x)g(x)
  • Derivative of f(x)/g(x)
  • Derivative of f(g(x))
  • Derivative of the inverse of f or f^(-1)
  • Mean Value Theorem
  • Intermediate Value Theorem
  • Extreme Value Theorem
  • Critical Point of f(x)
    Where f'(x)=0 or f'(x) is undefined
  • Local Minimum (First Derivative Test)

    Where f'(x) changes from negative to positive
  • Local Maximum (First Derivative Test)

    Where f'(x) changes from positive to negative
  • Local Minimum (Second Derivative Test)

    Where f'(a)=0 and f''(a)>0
  • Local Maximum (Second Derivative Test)

    Where f'(a)=0 and f''(a)<0
  • Inflection Point of f(x)
    Where f''(x) changes sign
  • Candidates Test

    Plug x-coordinates of all closed end points and critical points back into the original function f(x) to determine global/absolute maximum and minimum.
  • Global Maximum

    The largest y-value on the interval [a,b]. Based on the candidates test.
  • Global Minimum
    The smallest y-value on the interval [a,b]. Based on the candidates test.
  • L'Hospitals Rule
  • ln(1)=
    0