GENPHYSICS 2

• What is electric potential at energy at point p?

  1. Work done in moving 1 Coulomb of Charge from point P
  2. Work done in moving a small test charge from a certain space to point
  3. Work done in moving 1 Coulomb from infinity to a point P
  4. Work done in moving small  test charge from a infinity to a point P

  Answer: C. The electric potential at a point P is defined as the work done in moving 1 Coulomb of charge from infinity to that point. It represents the amount of electric potential energy per unit charge at that point.
• 11. The unit of electric potential is Volts (V)
• 12. Which of the following electric potential energy of a charged [article is dependent?

  1. Gravitational force
  2. Spring constant (K)
  3. Location in an electric field
  4. Mass of the particle

  The correct answer is C. The electric potential energy of a charged particle is dependent on its location in an electric field. The electric potential energy is a measure of the work required to move the charged particle from one point to another in the presence of an electric field.
• 13. Which is the change in the electric potential energy of an electron accelerated from rest through a potential difference of 12.0V? 

  1. 1.92 x 10^-18 Joule
  2. 3.50  x 10^-18 Joule
  3. -1.92  x 10^-18 Joule
  4. -3.50  x 10^-18 Joule

  The correct answer is option C: -1.92 x 10^-18 Joules.

  ΔPE = qΔV

  where ΔPE is the change in electric potential energy, q is the charge of the electron, and ΔV is the potential difference.

  The charge of an electron is approximately -1.6 x 10^-19 Coulombs.

  ΔPE = (-1.6 x 10^-19 C)(12.0 V)

  ΔPE = -1.92 x 10^-18 Joules
• 14. Which of the following units release to Electric Potential (V) and Electric Field strength (E)?

  1. 1 N.C = 1 V.m
  2. 1 N/C = 1 V/m
  3. 1 N/C = 1 V.m
  4. 1 N.C =  1 V/m

  Answer: B. 1 N/C = 1 V/m

  The unit for electric field strength (E) is volts per meter (V/m), and the unit for electric potential (V) is volts (V). Therefore, 1 Newton per Coulomb (N/C) is equivalent to 1 Volt per meter (V/m).
• The relationship between electric potential and electric field strength due to a charge between two charged plates separated by a certain distance is direct
• The relationship can be expressed as E = ΔV/d, where E is the electric field strength, ΔV is the potential difference, and d is the distance between the plates
• What is the electric field intensity of the uniform electric field if the potential difference from point A to point B as shown below is 12.0 V? Distance is 0.25m

  1. 6 N/C
  2. 24 N/C
  3. 48 N/C
  4. 240 N/C

  Answer: 48 N/C

  E = ΔV / d

  where ΔV is the potential difference and d is the distance between the points.

  In this case, the potential difference (ΔV) is given as 12.0 V and the distance (d) is given as 0.25 m.

  Plugging these values into the formula, we get:

  E = 12.0 V / 0.25 m

  E = 48 N/C

  Therefore, the electric field intensity of the uniform electric field is 48 N/C. Thus, the correct answer is C: 48 N/C.
• What is the charge of protons? +1.602 x 10^-19

  What is the charge ofelectron? -1.602 x 10^-19

  What is the charge of neutron? 0
• What happens to the magnitude of the electric potential (V) due to a point charge as the distance from it increases? 

  1. Increases
  2. Decreases
  3. Increases by half of its value
  4. Increases on a point then decreases after some time

  Answer: As the distance from a point charge increases, the magnitude of the electric potential (V) decreases.

  The electric potential due to a point charge follows an inverse relationship with distance. Specifically, the electric potential (V) is inversely proportional to the distance (r) from the point charge.
• What is the electric potential at 0.2 from point charge of magnitude equal to 2.6 nano-Coulomb?

  1. 117 Volts
  2. 120 Volts
  3. 234 Volts
  4. 420 Volts

  V = k * Q / r

  where V is the electric potential, k is the electrostatic constant (approximately 9 x 10^9 N m^2/C^2), Q is the charge of the point charge, and r is the distance from the point charge.

  In this case, the magnitude of the point charge is given as 2.6 nano-Coulombs (2.6 x 10^-9 C), and the distance from the point charge is given as 0.2 m.

  Plugging these values into the formula, we get:

  V = (9 x 10^9 N m^2/C^2) * (2.6 x 10^-9 C) / 0.2 m

  V ≈ 117 Volts
• Which is true about 1.5 V battery? 

  1. 0.75 Joules per every 1 coulomb of charge
  2. 1.5 joules per every 1 coulomb of charge
  3. 3 Joules per every 1 coulomb of charge
  4. 1 Joules per every 1 coulomb of charge

  The correct statement about a 1.5 V battery is:

  1.5 joules per every 1 coulomb of charge.

  The voltage of a battery represents the amount of electric potential energy per unit charge that the battery can provide. In this case, a 1.5 V battery can provide 1.5 joules of electric potential energy for every 1 coulomb of charge that flows through it.
• What is the voltage of 2 C with an electric potential energy of 5J?

  1. 1 V
  2. 1.5 V
  3. 2 V
  4. 2.5 V

  To determine the voltage (V) given a certain electric potential energy (PE) and charge (Q), you can use the formula:

  PE = Q * V

  V = PE / Q

  In this case, the electric potential energy (PE) is given as 5 nJ (5 x 10^-9 J), and the charge (Q) is given as 2 C.

  V = (5 x 10^-9 J) / 2 C

  V = 2.5 x 10^-9 V

  Therefore, the voltage of 2 C with an electric potential energy of 5 nJ is approximately 2.5 V. Thus, the correct answer is D: 2.5 V.
• The strength of the field at any point is: E = F/q0

  F = force in newton

  E = electric field strength in N/C

  q0 = magnitude of test charge in Coulomb
• The space or region surrounding the charged particle is called the Electric Field. 
• A unit of positive charge is used as a test charge to define or describe the electric field intensity or strength.
• The electric field lines represent the strength of the electric field.
• The electric field lines in a positive charge particle are UPWARD (palabas ang arrow)
• The electric field lines in a negative charge particle are towards (paloob ang arrow)
• More electric field = more strength or intensity of electric field
• Electric field strength is also known as Electric field intensity
• Electric field strength and force is directly proportional
• Electric field strength and magnitude of the test charge has no relationship with but the test charge is constant.
• Electric field strength is a vector quantity that has a direction and magnitude
• Positive charge has a same direction of  force and electric field strength

  Negative charge has a opposite direction of force and electric field strength
• Gravitational Potential energy is equal to mgh 

   M = mass

  G = gravitational pull

  H = height 

  Respectful to the ground
• Gravitational Potential energy is equal work done to the object to increase it’s height.
• In order to bring a object from a certain height in need to do WORK. 

  W = fd
• 3 types of potential energy

  1. Gravitational Potential Energy
  2. Electric Potential Energy
  3. Elastic Potential Energy
• Gravitational Potential Energy (GPE) is measured through its impact to the ground. Greater impact is equal to greater potential energy.
• To change the Gravitational Potential Energy (GPE) it need work you can throw it up or throw it away or bring it to a certain height.
• Force apply to increase it or lift it = WORK
• The force needed to move the charged particle is equal to the electric force experienced by the charge.

  F = q₀E
• The work done in moving this charge from point A to point B is this force multiplied by distance

  W = q₀Ed
• The work done in bringing a unit positive test charge from ground or infinity to another point B is called the electric potential at B. Electrical Potential is designated by letter V.

  V = W/q₀
• The unit of electric potential is volts.

  1 V(Volt )= 1 J(Joule)/C(Coulomb)
• Potential difference

  Vᴀʙ = Vʙ - Vᴀ 

  Vᴀʙ = Wᴀʙ/q₀
• Electric Potential energy (EPE) - electricity due to the charge of the particle.
• What is in between the charged oppositely (positive and negative) plates? Electric field
• The symbol of an electric field is 3 lines.