Nitrogen And hydrogen for ammonia shown by the following equation
N2(g) + 3H2(g) <-> 2NH3(g)
Calcualte the mass of nitrogen needed to form 6.8 tonnes of ammonia
Step 1: Work out n.o of moles of ammonia (Mr= 17)
6800000/17= 400000 moles of ammonia
Step 2: Use balanced equation and n.o of moles of ammonia to work out n.o of moles of nitrogen
-> Ratio of nitrogen to ammonia is 1:2
Therefore the n.o of moles of nitrogen is
Step 3: Work out mass of nitrogen Mr of N2 is 28
200000 x 28 = 5600000 = 5.6 tonnes