flashcards & answering structure

• what is the oxidation state of oxygen in superoxide

  -0.5
• what is the oxidation state of oxygen in peroxide?

  -1
• what is the oxidation state of oxygen in oxide?

  -2
• what is the oxidation state of oxygen in oxygen gas?

  zero
• explain why it is a redox reaction based on gain or loss of hydrogen and oxygen

  [reactant A] is reduced as it loses oxygen to form [product A]. [reactant B] is oxidized as it gains oxygen to form [product B]. since both oxidation and reduction occurs simultaneously, this reaction is a redox reaction
• explain, in terms of oxidation state, why this is a redox reaction

  [element] in [reactant A] is oxidized as its oxidation state increases from _ in [reactant A] to _ in [product A]. [element] in [reactant B] is reduced as its oxidation state decreases from _ in [reactant B] to _ in [product B]. since both oxidation and reduction are occurring simultaneously, this reaction is a redox reaction.
• explain, in terms of electrons, why this is a redox reaction

  [element] in [reactant A] is oxidized as it lost _ electrons to form [ion in product A]. [element] in [reactant B] is reduced as it gain _ electrons to form [ions in product B] since both oxidation and reduction occurs simultaneously, this reaction is a redox reaction
• [element] in [reactant A] is oxidized as its oxidation state increases from _ in [reactant A] to _ in [product A]. [element] in [reactant B] is reduced as its oxidation state decreases from _ in [reactant B] to _ in [product B]. since [element] is both oxidized and reduced, this reaction is a disproportionation reaction
• what to use to test for reducing agent in liquid state

  use potassium manganate(Vll)

  add acidified potassium manganate(Vll), a reducing agent, turning acidified potassium manganate (Vll) from purple to colourless

  oxidation state of the manganese decreases from +7 to +2, +7 being in purple and +2 being colourless
• what to use to test for oxidizing agent in liquid state

  use potassium iodide

  add potassium iodide, an oxidizing agent, will turn potassium iodide from colourless to brown due to formation of iodine

  oxidation state of iodine increases from -1 to 0 , -1 being colourless and 0 being brown
• what to use to test for reducing agent in gaseous state

  bring a filter paper dipped into acidified potassium manganate (Vll) near the gas. the acidified potassium manganate (Vll) will turn from purple to colourless
• what to use to test for oxidizing agent in gaseous state?

  bubble the gas into potassium iodide, potassium iodide turns from colourless to brown