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Boyle's law and Charles' law
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Cards (30)
Solids
More
compact
in nature
Liquids
Particles slightly
far apart
compared to solids, take the
shape
of their container
Gases
Particles very
far apart
, take up all the
space
in the container
Properties
of gases
Pressure
(P)
Volume
(
V
)
Temperature
(
T
)
Amount
(
n
)
Pressure
Force
acting on a specific area
Units
of pressure
atm (atmosphere)
mmHg (
millimeter mercury
)
Torr
psi (
pounds per square inch
)
kPa (
kilopascals
)
Volume
Three-dimensional
space
occupied by a gas
Units
of volume
milliliters
liters
cubic meters
cubic centimeters
Temperature
Measure of the average
kinetic energy
of the particles in an object
Units
of temperature
Fahrenheit
Celsius
Kelvin
Quantity
Measured in moles, one
mole
is equal to
6.022
x 10^23 units of a substance
Boyle's law relates
pressure
and volume at
constant temperature
and amount of substance
Boyle's law
Pressure is
inversely
proportional to volume at
constant
temperature
Volume
increases
Pressure
decreases
Volume
decreases
Pressure
increases
Demonstration
of Boyle's law
1. Put marshmallow in syringe
2. Observe what happens when syringe is pushed (volume decreases, pressure increases)
3. Observe what happens when syringe is released (volume increases, pressure decreases)
Boyle's law formula
P1 * V1 =
P2
*
V2
A gas occupies 12.3 liters at a pressure of 40.0 millimeter
mercury
, what is the volume when the pressure is increased to 120 millimeter
mercury
Solving
Boyle's law problem
1. Identify given values (
P1
, V1, P2,
V2
)
2. Substitute values into Boyle's law formula
3. Solve for V2
Applications
of Boyle's law
Action of a
syringe
Chips
bag at
higher
altitude
Breathing
(diaphragm movement)
Charles law relates
volume
and
temperature
at constant pressure
Charles law
Volume and
temperature
are directly
proportional
Volume increases
Temperature
increases
Volume
decreases
Temperature
decreases
Charles law formula
V1/T1
= V2/T2 (temperatures must be in
Kelvin
)
AC range contains
56.11
milliliters of gas at 311 Kelvin, determine the volume at
400
Kelvin
Solving
Charles law problem
1. Identify given values (
V1
,
T1
, T2)
2.
Substitute
values into Charles law formula
3. Solve for
V2
If a
540
ml nitrogen at 0 degree Celsius is heated to
100
degree Celsius, what will be the new volume
Solving
Charles law problem with temperature in Celsius
1. Convert temperatures to
Kelvin
2.
Substitute
values into Charles law formula
3. Solve for
V2
Applications
of Charles law
Hot air balloon
Ping pong balls
Baking
(bread, pastries)