Gas volumes

• 1 mole of any gas

  Occupies a volume of 24 dm³ at room temperature (20°C) and pressure (1 atm)
• Calculating the volume of a gas

  Number of moles x 24 dm³/mol
• The volume (V) in dm³ is the number of moles (n) multiplied by 24 dm³/mol
• 1 mole of any gas

  Occupies a volume of 24 dm³ at room temperature (20°C) and pressure (1 atm)
• Calculating the volume of a gas

  Number of moles x 24 dm³/mol
• The volume (V) in dm³ is the number of moles (n) multiplied by 24 dm³/mol
• Mole


  Unit of measurement for the amount of a substance, equal to the amount of a substance that contains as many elementary entities (e.g. atoms, molecules, ions) as there are atoms in 0.012 kilograms of carbon-12
• Volume


  The amount of 3-dimensional space occupied by a substance, object, or body, expressed in cubic units
• Calculating volume of gas

  1. Determine moles of gas

  2. Multiply moles by 24 dm3/mol
• Calculating volume of carbon dioxide produced

  • Given: 300 g calcium carbonate

  1. Calculate moles of calcium carbonate (300 g / 100 g/mol = 3 mol)

  2. Use balanced equation to determine 1 mol calcium carbonate produces 1 mol carbon dioxide

  3. Therefore, 3 mol calcium carbonate produces 3 mol carbon dioxide

  4. Volume of carbon dioxide = 3 mol * 24 dm3/mol = 72 dm3
• Calculating volume of hydrogen gas produced

  • Given: 325 g zinc

  1. Calculate moles of zinc (325 g / 65 g/mol = 5 mol)

  2. Use balanced equation to determine 1 mol zinc produces 1 mol hydrogen

  3. Therefore, 5 mol zinc produces 5 mol hydrogen

  4. Volume of hydrogen = 5 mol * 24 dm3/mol = 120 dm3
• Calculating volume of chlorine required

  • Given: 80 g calcium

  1. Calculate moles of calcium (80 g / 40 g/mol = 2 mol)

  2. Use balanced equation to determine 1 mol calcium requires 1 mol chlorine

  3. Therefore, 2 mol calcium requires 2 mol chlorine

  4. Volume of chlorine = 2 mol * 24 dm3/mol = 48 dm3