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biology
origins of genetic variation
8.2 transfer of genetic info
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abdul ahmed
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genotype
genetic
constitution
of organism
phenotype
expressed and observable characteristic of organism
due to
interaction
between genotype and environment
allele
different
forms
of the same
gene
found on the
locus
of a
chromosome
dominant
allele
always expressed in organism
whether it has 1 allele or 2
recessive
allele
characteristic only appears in
phenotype
when no dominant alleles are present
must be
homozygous
recessive to be seen (aa)
codominant
allele
2
dominant alleles contributing to the
phenotype
via a mix or both
characteristics
shown together
homozygous
same
alleles
(both dominant, AA or both
recessive
, aa)
heterozygous
one allele is dominant and one is
recessive
(Aa)
multiple alleles
gene with more than
2
alleles
reading pedigree diagrams
if trait is dominant = one parent
MUST
have trait
if trait is recessive =
neither
parent has to have trait
if trait is sex linked or
autosomal
how to work out if trait is sex linked or autosomal?
autosomal
= male and
female
have equal chance of being affected
sex-linked =
recessive
,
males
more affected than
female
how to tell if you are dealing with 2 non interacting unlinked genes?
9
:
3
:
3
:
1
ratio - as long as both parents are
heterozygous
what is a
sex
linked disorder?
disorder caused
by
faulty
gene
located on the x or y (
sex
)
chromosome
making the
disorder
more likely for one
gender.
what is autosomal linkage?
2
+ genes located on same (non sex)
chromosome
only
1
homologous pair of is needed for all
4
alleles to be present
for non linked genes,
2
homologous pairs are needed
example of autosomal linkage?
drosophila
-
fruit fly
boy colour and wing length are autosomally linked,
inherited
in
pairs
why are autosomally linked genes inherited in pairs?
genes on the same chromosome, are less likely to be crossed over during
meiosis
therefore they are
inherited
as if they are from the
same
gene
what is the chi squared test?
compares
frequencies
actually observed from an experiment vs the
expected
frequencies
how do you carry out the chi squared test?
o =
observed frequency
e =
expected frequency
(can be worked out by doing row total x
column total
/ overall total)
calculate
chi squared
test
calculate
dof
(
no. of categories-1
)
check to see if results are
significant
what to write when answering stats question:
null
hypothesis - no
difference
between observed and expected results
p value -
0.05
as results are not due to chance
dof - (n-1)
whether calculated value is higher or lower then the
critical
value
accept
or reject the null hypothesis