Sample question: 20 cm³ hydrochloric acid neutralized 25 cm³ calcium hydroxide 0.1 mol/dm³
1. Write C=, N=, V= for acid and alkali
2. Fill in: [Ca(OH)₂] = 0.1 mol/dm³, V = 0.025 dm³, V(HCl) = 0.02 dm³
3. Calculate moles Ca(OH)₂: 0.1 x 0.025 = 0.0025 mol
4. Use 2HCl:Ca(OH)₂ ratio, so 0.005 mol HCl
5. Concentration HCl = 0.005/0.02 = 0.25 mol/dm³
6. Concentration HCl = 0.25 x 36.5 = 9.125 g/dm³