Derivation of the kinetic theory model equation
1. Consider a cube with side lengths l, full of gas molecules
2. One molecule has mass m and is travelling with velocity u
3. Assume it collides with the right-most wall elastically, its change in momentum is mu - (-mu) = 2mu
4. Before this molecule can collide with this wall again it must travel a distance of 2l, therefore the time between collisions is t = 2l/u
5. Impulse = force = 2mu/2l = mu^2/l
6. Pressure = impulse/area = mu^2/l^3 = mu^2/V
7. Total pressure is the sum of all individual pressures = Nmu^2/V
8. Define mean square speed u^2 = (u^1)^2 + (u^2)^2 + ... + (u^n)^2 / N
9. Use Pythagoras' theorem to find the speed the molecules will be travelling at: c^2 = u^2 + v^2 + w^2, where u, v, w are the components in x, y, z directions
10. Assume mean square speed in each direction is the same, so u^2 = v^2 = w^2 and c^2 = 3u^2
11. Substitute this into the pressure equation to get p = (1/3)Nmc^2/V