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Alkanes,Alkenes and hydrocarbons
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Anisa Ahmed
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Alkanes
Saturated
hydrocarbons
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Shape around carbon atom in
saturated
hydrocarbons
Tetrahedral
Bond angle
109.5°
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The shape is
tetrahedral
as a result of the
four
bond pairs of electrons equally repelling
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Sigma (σ) bond
Single C-C bond formed by
overlap
of sp3 orbitals
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Rotation can occur around a
sigma
bond
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Reactivity of alkanes
Low
reactivity due to
high
bond enthalpies of C-C and C-H bonds and
low
polarity of σ-bonds
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Cracking
1. Conversion of
large
hydrocarbons to smaller molecules by breakage of C-C bonds
2. Requires
high
temperatures
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Cracking makes use of
excess
larger hydrocarbons and supplies
demand
for
shorter
ones
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The products of
cracking
are more valuable than the
starting
materials
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Complete combustion of alkanes
C8H18(g) + 12.5 O2(g) →
8CO2(g
) + 9
H2O
(l)
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Incomplete combustion of alkanes
1. CH4(g) + 3/2 O2(g) →
CO
(g) + 2 H2O(l)
2. CH4(g) + O2(g) →
C
(s) + 2 H2O(l)
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Carbon monoxide is highly
toxic
as it forms a stronger bond with
haemoglobin
than oxygen
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Catalytic cracking
1. Turns
straight
chain
alkanes
into branched/cyclic alkanes and
aromatic
hydrocarbons
2. Conditions: Slight pressure, High Temperature (450°C), Zeolite Catalyst
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Branched and
cyclic
hydrocarbons burn more cleanly and have higher
octane
numbers
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Substitution reactions of alkanes with chlorine/bromine
Alkane + Cl2/Br2 (UV
light
) →
Haloalkane
+ HCl/HBr
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Mechanism of alkane substitution with chlorine
1. Initiation: Cl2 → 2Cl·
2. Propagation: CH4 + Cl· → CH3· + HCl, CH3· + Cl2 → CH3Cl + Cl·
3. Termination: CH3· + Cl· → CH3Cl, CH3· + CH3· → CH3CH3
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The same mechanism applies to
substitution
with
bromine
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Further substitution of haloalkanes
1.
CH3Cl
+ Cl2 → CH2Cl2 +
HCl
2.
CH2Cl2
+ Cl2 → CHCl3 +
HCl
3.
CHCl3
+ Cl2 →
CCl4
+ HCl
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HCl is always the side product, never
H2
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Overall reaction equations
CH4 + 4 Cl2 →
CCl4
+ 4
HCl
CH3F + 3 Cl2 →
CFCl3
+ 3
HCl
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Alkenes
Unsaturated
hydrocarbons
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Alkenes
Contain a
carbon-carbon
double
bond somewhere in their structure
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Alkenes
Ethene
Propene
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Numbers need to be added to the name when
positional isomers
can occur
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C=C double covalent bond
Consists of one
sigma
(σ) bond and one
pi
(π) bond
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π bonds
Are
exposed
and have
high
electron density
They are therefore vulnerable to attack by species which 'like' electrons: these species are called
electrophiles
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Formation of π bond in alkenes
Sideways
overlap of two p orbitals on each carbon atom forming a π-bond above and below the plane of molecule
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π bond
Is
weaker
than the σ bond
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Arrangement of bonds around >C=C<
Planar
and has the bond angle
120o
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Formation of σ bond in alkenes
Two sp2
orbitals (one from each carbon) overlap to form a single
C-C
bond called a sigma σ bond
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Stereoisomers
Have the
same
structural
formulae but have a different
spatial
arrangement
of atoms
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Z stereoisomerism
Alkenes can exhibit this type of isomerism due to
restricted
rotation about the C=C bond
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But-1-ene
is a structural isomer of But-2-ene but does not show
E-Z
isomerism
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Naming E-
Z
stereoisomers
1. Determine the
priority
groups on both sides of the double bond
2. If the priority atom is on the
same
side of the double bond it is labelled Z
3. If the priority atom is on the
opposite
side of the double bond it is labelled
E
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Cis-trans
isomerism
A special case of
E-Z
isomerism in which two of the
substituent
groups are the same
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1,2-dichloroethene
Polar
molecule with polar C-Cl bonds on the same side, higher boiling point due to
dipole-dipole
attractions
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1,2-dichloroethene
Non-polar molecule with polar C-Cl bonds on opposite sides,
lower
boiling point due to only
London
forces
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Alkenes
Relatively
reactive
because of the relatively
low
bond enthalpy of the π-bond
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Addition reaction of alkenes with hydrogen
Alkene +
H2
→
Alkane
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Electrophilic addition reaction of alkenes with bromine/chlorine
Alkene +
Br2
→
Dihaloalkane
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