Save
...
Edexcel Maths
Year 2
Pure
Save
Share
Learn
Content
Leaderboard
Share
Learn
Created by
Connor McKeown
Visit profile
Cards (48)
What is the main concept behind manipulating algebraic fractions?
Algebraic fractions can be
manipulated
in the
same way as numeric fractions.
View source
How do you add the algebraic
fractions
x
x
+
4
+
\frac{x}{x + 4} +
x
+
4
x
+
4
x
−
1
\frac{4}{x - 1}
x
−
1
4
?
\frac{x(x - 1) +
4(x + 4)}{(x + 4)(x - 1)} =
x
2
+
3
x
+
16
(
x
+
4
)
(
x
−
1
)
\frac{x^2 + 3x + 16}{(x + 4)(x - 1)}
(
x
+
4
)
(
x
−
1
)
x
2
+
3
x
+
16
View source
What is the result of
multiplying
the algebraic
fractions
x
x
+
4
×
4
x
−
1
\frac{x}{x + 4} \times \frac{4}{x - 1}
x
+
4
x
×
x
−
1
4
?
4
x
(
x
−
1
)
(
x
+
4
)
\frac{4x}{(x - 1)(x + 4)}
(
x
−
1
)
(
x
+
4
)
4
x
View source
How do you divide the algebraic
fractions
x
x
+
4
÷
4
x
−
1
\frac{x}{x + 4} \div \frac{4}{x - 1}
x
+
4
x
÷
x
−
1
4
?
x
(
x
−
1
)
4
(
x
+
4
)
\frac{x(x - 1)}{4(x + 4)}
4
(
x
+
4
)
x
(
x
−
1
)
View source
What is the relationship between a fraction of the form
F
(
x
)
G
(
x
)
\frac{F(x)}{G(x)}
G
(
x
)
F
(
x
)
and its quotient and
remainder
?
F
(
x
)
G
(
x
)
=
\frac{F(x)}{G(x)} =
G
(
x
)
F
(
x
)
=
Q
(
x
)
+
Q(x) +
Q
(
x
)
+
r
G
(
x
)
\frac{r}{G(x)}
G
(
x
)
r
, where
Q
(
x
)
Q(x)
Q
(
x
)
is the quotient and
r
r
r
is the remainder.
View source
How can an improper fraction be expressed using algebraic division?
An improper fraction can be
rewritten
as a
proper
fraction plus a
quotient.
View source
What must you do before using partial fractions on an
improper
fraction?
You must first perform
long division
to express it as a proper
fraction.
View source
What is a linear factor in the context of partial fractions?
A
linear factor
is of the form
a
x
+
ax +
a
x
+
b
b
b
.
View source
What is an improper fraction?
An improper fraction is one where the degree of the numerator is
greater
than or
equal
to the degree of the denominator.
View source
What is proof by contradiction?
Proof by contradiction assumes a statement is
false
and shows that this leads to a
contradiction.
View source
How can any even number
n
n
n
be expressed?
Any even number
n
n
n
can be written as
n
=
n =
n
=
2
k
2k
2
k
for some integer
k
k
k
.
View source
How can any odd number
n
n
n
be expressed?
Any
odd
number
n
n
n
can be written as
n
=
n =
n
=
2
k
+
2k +
2
k
+
1
1
1
for some integer
k
k
k
.
View source
How can rational numbers be expressed?
Rational numbers
can be written in the form
a
b
\frac{a}{b}
b
a
, where
a
a
a
and
b
b
b
are
integers.
View source
How can irrational numbers be expressed?
Irrational numbers cannot
be
written
in the form
a
b
\frac{a}{b}
b
a
.
View source
What is the process of proving statements by contradiction?
Assume
the statement is
false.
Show that this
assumption
leads to a
contradiction.
Conclude
that the
original
statement must be
true.
View source
What are the steps to prove that there are
infinitely
many prime numbers by contradiction?
Assume
there are a
finite number
of
primes.
Define
K
=
K =
K
=
p
1
p
2
p
3
…
p
n
+
p_1 p_2 p_3 \ldots p_n +
p
1
p
2
p
3
…
p
n
+
1
1
1
.
Show
K
K
K
is
not divisible
by any of the
primes.
Conclude
that there must be infinitely many
primes.
View source
What are the steps to prove that there exist no integers a and b such that
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
?
Assume integers a and b exist such that
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
.
Divide through by 7 to get
3
a
+
3a +
3
a
+
2
b
=
2b =
2
b
=
1
1
1
.
Show that
3
a
+
3a +
3
a
+
2
b
2b
2
b
must also be an integer.
Conclude that the assumption is false.
View source
What are the important definitions related to fractions and statements?
Negation
: A statement implying the original statement is incorrect.
Contradiction
: Incompatibility between two statements.
Improper fraction
: Degree of numerator ≥ degree of denominator.
View source
What is the first example used to prove by contradiction in the study material?
Prove that there are infinitely
many prime
numbers.
View source
What assumption is made in the first example regarding prime numbers?
That there are a
finite
number of
prime numbers.
View source
What is the significance of the number
K
=
K =
K
=
p
1
p
2
p
3
…
p
n
+
p_1 p_2 p_3 \ldots p_n +
p
1
p
2
p
3
…
p
n
+
1
1
1
in the proof of infinite primes?
It is
not divisible
by any of the prime numbers, leading to a
contradiction.
View source
What conclusion can be drawn from the contradiction in the first example about prime numbers?
There
must be an
infinite
number of
prime numbers.
View source
What is the second example used to prove by contradiction in the study material?
Prove that there exist no integers a and b such that
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
.
View source
What assumption is
made
in the second example regarding integers a and b?
That there are integers a and
b
such that
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
.
View source
What happens when we divide the equation
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
by 7?
It
simplifies
to
3
a
+
3a +
3
a
+
2
b
=
2b =
2
b
=
1
7
\frac{1}{7}
7
1
.
View source
Why is the equation
3
a
+
3a +
3
a
+
2
b
=
2b =
2
b
=
1
7
\frac{1}{7}
7
1
a contradiction?
Because
3
a
+
3a +
3
a
+
2
b
2b
2
b
must be an
integer
, but
1
7
\frac{1}{7}
7
1
is
not.
View source
What is the conclusion drawn from the second example regarding integers a and b?
There are no integers a and b such that
21
a
+
21a +
21
a
+
14
b
=
14b =
14
b
=
1
1
1
.
View source
What are the steps involved in
the
partial fraction method as illustrated in Example 3?
Set up the equation
:
6
x
2
+
5
x
−
2
x
(
x
−
1
)
(
2
x
+
1
)
≡
A
x
+
\frac{6x^2 + 5x - 2}{x(x-1)(2x+1)} \equiv \frac{A}{x} +
x
(
x
−
1
)
(
2
x
+
1
)
6
x
2
+
5
x
−
2
≡
x
A
+
B
x
−
1
+
\frac{B}{x-1} +
x
−
1
B
+
C
2
x
+
1
\frac{C}{2x+1}
2
x
+
1
C
Make all denominators the same.
Equate
the
numerators.
Use substitution
to
find constants
A, B,
and C.
View source
How do you find the constants A, B, and C in the partial fraction decomposition?
By
substituting specific values
of
x
to simplify the
equation.
View source
What values of x are chosen for substitution to find constants in Example 3?
x =
1
and x =
0.
View source
What is the result of substituting x = 1 in the equation to find B?
It leads to
3
B
=
3B =
3
B
=
9
⇒
B
=
9 \Rightarrow B =
9
⇒
B
=
3
3
3
.
View source
What is the result of substituting x = 0 in the equation to find A?
It leads to
−
A
=
-A =
−
A
=
−
2
⇒
A
=
-2 \Rightarrow A =
−
2
⇒
A
=
2
2
2
.
View source
How do you find the constant C after determining A and B?
By
substituting
another value of
x
into the equation.
View source
What is the
final
result of the
partial fraction decomposition
in Example
3
?
6
x
2
+
5
x
−
2
x
(
x
−
1
)
(
2
x
+
1
)
≡
2
x
+
\frac{6x^2 + 5x - 2}{x(x-1)(2x+1)} \equiv \frac{2}{x} +
x
(
x
−
1
)
(
2
x
+
1
)
6
x
2
+
5
x
−
2
≡
x
2
+
3
x
−
1
−
4
2
x
+
1
\frac{3}{x-1} - \frac{4}{2x+1}
x
−
1
3
−
2
x
+
1
4
.
View source
What modification is needed when dealing with repeated linear factors in partial fractions?
Include an
extra fraction
for each repeated
linear factor.
Example: For
2
x
2
+
2
x
−
18
x
(
x
−
3
)
2
\frac{2x^2 + 2x - 18}{x(x-3)^2}
x
(
x
−
3
)
2
2
x
2
+
2
x
−
18
, use:
A
x
+
\frac{A}{x} +
x
A
+
B
x
−
3
+
\frac{B}{x-3} +
x
−
3
B
+
C
(
x
−
3
)
2
\frac{C}{(x-3)^2}
(
x
−
3
)
2
C
.
View source
How would you set up the
partial fraction decomposition
for
10
x
2
−
10
x
+
17
(
2
x
+
1
)
(
x
−
3
)
2
\frac{10x^2 - 10x + 17}{(2x + 1)(x - 3)^2}
(
2
x
+
1
)
(
x
−
3
)
2
10
x
2
−
10
x
+
17
?
A
2
x
+
1
+
\frac{A}{2x + 1} +
2
x
+
1
A
+
B
x
−
3
+
\frac{B}{x - 3} +
x
−
3
B
+
C
(
x
−
3
)
2
\frac{C}{(x - 3)^2}
(
x
−
3
)
2
C
.
View source
How would you set up the
partial fraction decomposition
for
2
x
(
x
+
2
)
2
\frac{2x}{(x + 2)^2}
(
x
+
2
)
2
2
x
?
A
x
+
2
+
\frac{A}{x + 2} +
x
+
2
A
+
B
(
x
+
2
)
2
\frac{B}{(x + 2)^2}
(
x
+
2
)
2
B
.
View source
What are the basic algebraic operations mentioned in the cheat sheet?
Addition
Multiplication
Division
View source
What is the polynomial given in the division example?
x
3
+
x^3 +
x
3
+
x
2
+
x^2 +
x
2
+
0
x
−
7
0x - 7
0
x
−
7
.
View source
What is the divisor in the division example?
x
−
3
x - 3
x
−
3
.
View source
See all 48 cards