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Cards (8)
Aldehydes and Ketones (Fehling's Solution)
Just
aqueous solution
of
CuSO4
Add
compound
to
be
tested
and
Fehling's Solution
to
two separate
test tubes
Place them in a
water bath
and heat them till
same temperature
(
30 - 35
degrees Celsius)
Aldehydes:
alkaline
solution of
blue
Cu (
II
) ions is
reduced
to
red
Cu (
I
) ions by
aldehydes
Ketones:
cannot be oxidised
-
no reaction
Positive result: for
aldehydes
;
blue
solution makes
brick red
precipitate
Ionic equation -
RCHO
+
2Cu2
+ +
5OH-
->
RCOO-
+
Cu2O
+
3H20
Aldehydes and Ketones (Tollen's Reagent)
Compound to be tested and Tollen's reagent added to
separate test tubes
and heated to
same
temperature (
30-35
degrees celsius) in a
water bath
Aldehydes: formation of a
silver mirror
from the
reduction
of the
Ag+
ions to
metallic
silver
as they are
oxidised
to make
carboxylic acids
Ketones: cannot be
oxidised
so
no result
Ionic equation -
RCHO
+
2Ag-
+
3OH-
->
RCOO-
+
2Ag
+
2H20
Alcohol Oxidation State
Orange
acidified potassium dichromate
K2Cr2O7
Turned
green
by
primary
and
secondary
alcohols:
bright orange
Cr in 6+ oxidation state
reduced
to
green
3+
Cr
Primary alcohol ->
aldehyde
->
carboxylic acid
Secondary alcohol ->
ketone
Tertiary alcohols
cannot be oxidised
Halide Ions
Add
HNO3
(
acidifies
solution to remove any
CO2-
ions which would give a
false positive
for
Cl
; not
HCl
as
Cl
would also give a false positive )
Add
AgNO3
Cl- ->
white
Br- ->
cream
I- ->
yellow
NH4
to tell AgBr and AgCl apart: AgCl
redissolves
in
dilute
ammonia, AgBr redissolves in
concentrated
ammonia
AgI is
too insoluble
to redissolve
Sulfate Ions
Add HCl to solution (acidify solution to remove any CO2- ions which would form a white precipitate of
BaCO2
and give a
false positive
)
Add
BaCl2
Presence of sulfates gives a
white precipiate
Ba2+ (aq) + SO4 2- (aq) -> BaSO4 (s)
CO3 2- or HCO3-
Add a
few drops
of dilute HNO3 to the solid/solution being tested
Fizzing
or
bubbles
indicates the presence of carbonate through production of
CO2
2H+ + CO3 2- -> CO2 + H2O
H+ + HCO3- -> CO2 + H2O
Hydroxide ions
Forms
insoluble
precipitate using range of
metal
ions
Alkaline
, turns red litmus or universal indicator
blue
/purple
Mg2
+ - white ppt
Cu2
+ - blue ppt
Fe3
+ - brown ppt
Ionic equation is
metal
ion +
hydroxide
ion -> metal hydroxide
White metal precipitates
Mg(OH)2
Ca(OH)2
SrSO4
BaSO4