REACTION OF SODIUM IODIDE AND CONCENTRATED SULFURIC ACID?
NaI (s) + H2SO4 (l) -> NaHSO4 (s) + HI (g)
2H+ + 2I- + H2SO4 (l) -> SO2 (g) + 2H2O (l) + I2 (s)
-> passes through redox reaction
8H+ + 8I- + H2SO4 (l) -> H2S (g) + 4H2O (l) + 4I2 (s)
-> may also see some yellow solid sulfur
-> H2S (g) = bad egg smell
-> I- strong enough reducing agent to reduce H2SO4 -> SO2 -> H2S