“Any 2 particles of matter attract 1 another with a force directly proportional to the product of their masses & inversely proportional to the square of the distance bw/ them”
Gravitational force [proportional to (check)] (m1 * m2) / distance^2
Consider the force of attraction bw/ 2 students…
2 students sitting 1.5 m apart
Student 1 = 50 kg
Student 2 = 70 kg
Gravitational force [proportional to (check)] (m1 * m2) / distance2
F = G x (m1 * m2) / l^2
‘Big G’ Proportional constant = 0.000000000067
F = (6.7 x 10-11 m3kg-1s-2) * ((70 kg)(50 kg))/(1.5 m)2
F = 10422 x 10-11 = 1.04 x 10-7 N
What about the attraction of the student to the earth?
Student 1 = 50 kg
G = 0.000000000667 m3kg-1s-2
F = G x (m1 * m2) / l^2
F = (6.7 x 10^-11 m3/kg/s^2) * ((5.97 x 10^24 kg)(50 kg)/(6.38 x 106 m)^2
F = 491 N Weight
Weight = mass x gravity
W = m * g
Are Weight & Mass the same thing?
No
Weight vs Mass:
An object's weight represents the force of attraction bw/ the earth & the object
Mass represents the quantity of matter of which body is composed
Weight vs Mass:
F = (6.7 x 10^-11 m3/kg/s^2) * ((5.97 x 10^24 kg)(50 kg)/(6.38 x 106 m)^2
F = 491 N Weight
F = 491 N / 50 kg = 9.81 m/s^2 Gravitational pull = g
Weight = m x g
Where does little g come from?
If you want Proof of Little g
Little g is the net acceleration that is imparted to objects due to the combined effect of gravitation (from distribution of mass within Earth) & the centrifugal force (from the Earth’s rotation)
Little ‘g’ = G * (mass of earth / l^2)
Where does little g come from?
g = (6.7 x 10^-11 m^3/kg/s^2) * ((5.97 x 10^24 kg)(50 kg)/(6.38 x 106 m)^2
= - 9.81 m/s^2
Why is this important?
The force acting on the body in relation to its mass is one of the most significant forces in biomechanics
Most consistent force acting upon us daily
No horizontal movement exists unless we overcome this force
All projectile motion is governed by gravitational forces
The mass of the Earth is unchanging, so if we reduce the mass of a body, it will be influenced less