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Further maths
Calculus
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Cards (18)
How
does the gradient of the curve change?
The
gradient
changes
depending
on
the
position
along
the
curve.
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What does the gradient of the tangent at a point on the curve represent?
It
represents
the
steepness
of
the
curve
at
that
point.
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How can you approximate the
gradient
at a point on the curve?
By calculating the gradient of a
chord
between two points on the curve.
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What happens to the
gradient
of the chord as the points get closer together?
The gradient of the chord approaches the gradient of the
tangent
.
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What is the
gradient
of the chord between the points (2, 4) and (3, 9)?
The gradient is
5
.
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What is the
gradient
of the chord between the points (2, 4) and (2.5, 6.25)?
The gradient is
4.5
.
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What is the
gradient
of the
chord
between the points (2, 4) and (
2.01
, 4.41)?
The gradient is
4.01
.
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What is the
formula
for the
gradient
of a chord?
The formula is
\(\frac{Y_2 - Y_1}{X_2 - X_1}\)
.
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What does the
limit
of the
gradient
approach as the
distance
\(H\)
approaches
zero?
The limit approaches \(2x\) for the
curve
\(y =
x^2
\).
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What is the result of
differentiating
\(y = x^2\)
?
The result is \(\frac{dy}{dx} =
2x
\).
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What is the result of
differentiating
\(y = x^3\)
?
The result is \(\frac{dy}{dx} =
3x^2
\).
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What is the general rule for
differentiating
\(
y
= x^n\)?
The result is \(\frac{dy}{dx} =
nx^{n-1}
\).
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What is the process of going from the curve to its gradient called?
The process is called
differentiation
.
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What
notation
is commonly used for
differentiation
?
The notation is
\(\frac{dy}{dx}\)
.
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What are the steps to
differentiate
\(y = x^2\)?
Identify the function: \(y = x^2\).
Apply the
power rule
: bring down the
exponent
.
Reduce the exponent by one.
Result: \(\frac{dy}{dx} =
2x
\).
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What are the steps to
differentiate
\(y = x^3\)?
Identify the function: \(y = x^3\).
Apply the
power rule
: bring down the
exponent
.
Reduce the exponent by one.
Result: \(\frac{dy}{dx} =
3x^2
\).
View source
What is the process of
differentiation
for
polynomial functions
?
Identify the power of \(x\).
Apply the
power rule
: multiply by the
exponent
.
Decrease the exponent by one.
Repeat for each term in the polynomial.
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What is the significance of the
limit
as \(H\) approaches zero in
differentiation
?
It allows for the precise calculation of the
gradient
at a specific point.
It ensures that the approximation of the gradient becomes exact.
It leads to the
derivative
function.
View source
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