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AP Calculus AB
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Created by
Asal Abdulkadir
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Cards (22)
What is the name of the student in the study material?
Asal
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What is the
ID number
of the student?
1
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What is the date mentioned in the study material?
10/11/19
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What
period
is indicated in the study material?
9th
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What subject is being practiced in the study material?
Calculus
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What is the task described in the study material regarding the graph of *f(x)*?
Sketch an approximate graph of *
f’(x)
*
based on the graph of *f(x)*.
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What are the steps indicated for graphing derivatives?
Given the graph of *f(x)*.
Sketch an approximate graph of *f’(x)*.
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The
derivative
of
sin(x)
is
cos(x)
.
What is the first function to
differentiate
in the quiz?
f(x)
=
x^3
+
4x^2
- 4x +
1
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What is the
derivative
of the function
f
(
x
)
=
f(x) =
f
(
x
)
=
x
3
+
x^3 +
x
3
+
4
x
2
−
4
x
+
4x^2 - 4x +
4
x
2
−
4
x
+
1
1
1
?
f
′
(
x
)
=
f'(x) =
f
′
(
x
)
=
3
x
2
+
3x^2 +
3
x
2
+
8
x
−
4
8x - 4
8
x
−
4
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What is the
second
function to
differentiate
in the quiz?
y = 4x^3 - 3x^2 - 9
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What is the
derivative
of the
function
y
=
y =
y
=
4
x
3
−
3
x
2
−
9
4x^3 - 3x^2 - 9
4
x
3
−
3
x
2
−
9
?
y
′
=
y' =
y
′
=
12
x
2
−
6
x
12x^2 - 6x
12
x
2
−
6
x
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What is the
third
function to
differentiate
in the quiz?
y = \frac{
x^4
}{2x^2} - 3
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What is the
derivative
of the
function
y
=
y =
y
=
x
4
2
x
2
−
3
\frac{x^4}{2x^2} - 3
2
x
2
x
4
−
3
?
y
′
=
y' =
y
′
=
2
x
2
−
4
2
x
2
=
\frac{2x^2 - 4}{2x^2} =
2
x
2
2
x
2
−
4
=
x
2
−
2
x
2
\frac{x^2 - 2}{x^2}
x
2
x
2
−
2
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What is the
function
for which we need to find the
derivative
in
problem
4
?
f(x)
= 6x^5 - 5x^3 + 3x^2 - 10x + 2
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What is the
derivative
of the function
f
(
x
)
=
f(x) =
f
(
x
)
=
6
x
5
−
5
x
3
+
6x^5 - 5x^3 +
6
x
5
−
5
x
3
+
3
x
2
−
10
x
+
3x^2 - 10x +
3
x
2
−
10
x
+
2
2
2
?
f
′
(
x
)
=
f'(x) =
f
′
(
x
)
=
30
x
4
−
15
x
2
+
30x^4 - 15x^2 +
30
x
4
−
15
x
2
+
6
−
10
6 - 10
6
−
10
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What are the steps to find the
derivative
of a sum of
functions
?
Use the
rule
:
A
(
x
)
=
A(x) =
A
(
x
)
=
f
(
x
)
+
f(x) +
f
(
x
)
+
g
(
x
)
g(x)
g
(
x
)
Differentiate
each function separately:
A
′
(
x
)
=
A'(x) =
A
′
(
x
)
=
f
′
(
x
)
+
f'(x) +
f
′
(
x
)
+
g
′
(
x
)
g'(x)
g
′
(
x
)
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If
A
(
x
)
=
A(x) =
A
(
x
)
=
f
(
x
)
+
f(x) +
f
(
x
)
+
g
(
x
)
g(x)
g
(
x
)
, how do you find
A
′
(
3
)
A'(3)
A
′
(
3
)
?
Calculate
A
′
(
3
)
=
A'(3) =
A
′
(
3
)
=
f
′
(
3
)
+
f'(3) +
f
′
(
3
)
+
g
′
(
3
)
g'(3)
g
′
(
3
)
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What are the steps to find the
derivative
of a difference of
functions
?
Use the
rule
:
B
(
x
)
=
B(x) =
B
(
x
)
=
f
(
x
)
−
g
(
x
)
f(x) - g(x)
f
(
x
)
−
g
(
x
)
Differentiate
each function separately:
B
′
(
x
)
=
B'(x) =
B
′
(
x
)
=
f
′
(
x
)
−
g
′
(
x
)
f'(x) - g'(x)
f
′
(
x
)
−
g
′
(
x
)
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If
B
(
x
)
=
B(x) =
B
(
x
)
=
f
(
x
)
−
g
(
x
)
f(x) - g(x)
f
(
x
)
−
g
(
x
)
, how do you find
B
′
(
3
)
B'(3)
B
′
(
3
)
?
Calculate
B
′
(
3
)
=
B'(3) =
B
′
(
3
)
=
f
′
(
3
)
−
g
′
(
3
)
f'(3) - g'(3)
f
′
(
3
)
−
g
′
(
3
)
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What are the steps to find the
derivative
of a product of functions?
Use the
product rule
:
k
(
x
)
=
k(x) =
k
(
x
)
=
f
(
x
)
⋅
g
(
x
)
f(x) \cdot g(x)
f
(
x
)
⋅
g
(
x
)
Differentiate
:
k
′
(
x
)
=
k'(x) =
k
′
(
x
)
=
f
′
(
x
)
g
(
x
)
+
f'(x)g(x) +
f
′
(
x
)
g
(
x
)
+
f
(
x
)
g
′
(
x
)
f(x)g'(x)
f
(
x
)
g
′
(
x
)
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If
k
(
x
)
=
k(x) =
k
(
x
)
=
f
(
x
)
⋅
g
(
x
)
f(x) \cdot g(x)
f
(
x
)
⋅
g
(
x
)
, how do you find
k
′
(
1
)
k'(1)
k
′
(
1
)
?
Calculate
k
′
(
1
)
=
k'(1) =
k
′
(
1
)
=
f
′
(
1
)
g
(
1
)
+
f'(1)g(1) +
f
′
(
1
)
g
(
1
)
+
f
(
1
)
g
′
(
1
)
f(1)g'(1)
f
(
1
)
g
′
(
1
)
View source
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