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Maths
Non Calculator Practice Questions
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Cards (10)
Simplify: [3x/4]+[2x/5]
[3xX5/20]+[2xX4/20]=[15x+8x/20]=[23x/20]
Simplify: [5/sqrt(3)]
[5/sqrt(3)]X[sqrt(3)/sqrt(3)]=[5sqrt(3)/3]
Simplify: sqrt(50)+sqrt(8)
sqrt(50)=5sqrt(2)
sqrt(8)=2sqrt(2)
5sqrt(2)+2sqrt(2)=7sqrt(2
)
Solve for x: 3^[2x+1]=27
3^[2x+1]=3^[3]
2x+1=3
2x=2
x=1
Complete the square for:x^[2]+6x-7
(x+3)^[2]=x^[2]+6x+9
(x+3)^[2]-16
Find the
gradient
of a line through points A(2,3)and B(4,7)
Gradient=[
y2-y1
/
x2-x1
]=[7-3/4-2]=[
4/2
]=2
State the equation of a line parallel to y=3x+2 passing through the point (1,4).
Parallel lines have the same gradient, so y=3x+c. Substitute (1,4) to find c: 4=3(1)+c
c=1
y=3x+1
Simplify: (a^[3]
b^[-2]
)X(a^[-1]
b^[4]
)
a^[3+(-1)]b^[-2+4]=a^[2]
b^[2]
What are the
circle theorems
for angles subtended by the same
arc
?
Angles subtended by the same arc are equal.
Angles in a
semicircle
are right angles (
90°
).
The angle at the center is twice the angle at the
circumference
.
Given a is directly proportional to b^[2], write the equation for a in terms of b if a=50 when b=5.
Set up the proportional relationship: a=kb^[2]
Substitute to find k: 50=kx5^[2]
k=2
Final equation: a=2b^[2]