Both aldehydes and ketones can be reduced forming primary and secondary alcohols respectively
Reduction of aldehydes and ketones with NaBH4
NaBH4 is sodiumborohydride
It's mechanism is nucleophilicaddition with the nucleophile being H- (hydride ion)
In acidic conditions
E.g. CH3CH2CHO + 2 [H] --> CH3CH2CH2OH which is proponal --> propan-1-ol
[H] is the reducing agent
In the reduction of an asymmetrical ketone, a chiral center would be produced resulting in a racemic mixture of optical isomers because there's equal chance of either side of the carbon (double bond ) being attacked due to planar nature of carbonyl
In nucleophilic additions with cyanide ions , KCN is used instead of HCN because it's very volatile and highly toxic liquid while KCN is a stable solid
Due to C=O being planar, there's an equal chance of it being attacked from either side which results in a racemic mixture that would be optically inactive