What happens when the conc of H+ is higher than the original conc of acid when calculating for a weak acid?
Rearange to put it in a quadratic form:
x² + 0.2x - (0.2 x 0.1) = 0
Use the quadratic formula:
Concentrations cannot be negative so e 𝑥 = [H3O+] = 0.0732 M.
pH = - log10 [H3O+] = 1.135