Save
Chemistry
Physical 1
The Equilibrium Constant
Save
Share
Learn
Content
Leaderboard
Share
Learn
Created by
Noah
Visit profile
Cards (31)
What is the equilibrium constant denoted as?
K<sub>c</sub>
View source
What type of reactions are reversible reactions?
Reactions that can proceed in both directions
View source
In the reaction aA + bB ⇌ cC + dD, who are the reactants?
A and B
View source
What does the equilibrium constant K<sub>c</sub> indicate?
Balance between reactants and products at equilibrium
View source
What does a large K<sub>c</sub> value indicate about the reaction?
The reaction favors the formation of products
View source
What does a small K<sub>c</sub> value indicate about the reaction?
The reaction favors the formation of reactants
View source
What does K<sub>c</sub> being around 1 indicate?
Both
reactants
and
products
are present in
comparable
amounts
View source
What does a large K<sub>c</sub> value imply about the color of the reaction mixture?
The
mixture
is
mostly
colorless
View source
What is the expression for K<sub>c</sub> in the reaction 2NO<sub>2</sub> ⇌ N<sub>2</sub>O<sub>4</sub>?
K<sub>c</sub> = [N<sub>
2
</sub>O<sub>4</sub>] / [NO<sub>2</sub>]<sup>2</sup>
View source
If [NO<sub>2</sub>] = 0.2 mol/dm<sup>3</sup> and [N<sub>2</sub>O<sub>4</sub>] = 0.8 mol/dm<sup>3</sup>, what is K<sub>c</sub>?
K<sub>c</sub> =
20
View source
What is the purpose of an ICE table in calculating K<sub>c</sub>?
Organizes
concentrations
at different stages
Stands for Initial, Change, Equilibrium
View source
In the reaction 2SO<sub>3</sub> ⇌ 2SO<sub>2</sub> + O<sub>2</sub>, what is the initial concentration of SO<sub>3</sub>?
0.15 mol/
dm<sup>3</sup>
View source
If the equilibrium concentration of O<sub>2</sub> is 0.05, what is x in the ICE table?
x =
0.05
View source
What is the equilibrium concentration of SO<sub>2</sub> in the reaction 2SO<sub>3</sub> ⇌ 2SO<sub>2</sub> + O<sub>2</sub>?
0.10
mol/
dm<sup>3</sup>
View source
How do you calculate K<sub>c</sub> using equilibrium concentrations?
K<sub>c</sub> = (([
SO<sub>2</sub>
]<sup>2</sup> × [O<sub>2</sub>]) ÷ [
SO<sub>3</sub>
]<sup>2</sup>)
View source
What is the calculated value of K<sub>c</sub> for the reaction?
K<sub>c</sub> = 0.2
mol<sup>-1</sup>
dm<sup>3</sup>
View source
What happens to K<sub>c</sub> if the fraction is top heavy?
We can
swap
the
signs
of
the
powers
View source
What are the units for K<sub>c</sub> if the fraction is top heavy?
mol<sup>-1</sup>
dm<sup>3</sup>
View source
How does temperature affect K<sub>c</sub>?
K
<sub>c</sub> is
temperature-dependent
View source
What happens to K<sub>c</sub> if the forward reaction is exothermic and temperature increases?
K<sub>c</sub>
decreases
View source
What happens to K<sub>c</sub> if the forward reaction is endothermic and temperature increases?
K<sub>c</sub>
increases
View source
In the Haber process, what happens to K<sub>c</sub> when temperature is increased?
K<sub>c</sub>
decreases
View source
How does changing the concentration of reactants affect K<sub>c</sub>?
K
<sub>c</sub> is
not
affected
View source
What does increasing the concentration of reactants do to the equilibrium position?
Shifts equilibrium to the
right
View source
What does increasing the concentration of products do to the equilibrium position?
Shifts equilibrium to the left
View source
In the reaction PCl<sub>5</sub> ⇌ PCl<sub>3</sub> + Cl<sub>2</sub>, what happens when PCl<sub>5</sub> concentration is increased?
Equilibrium shifts to the
right
View source
In the reaction PCl<sub>5</sub> ⇌ PCl<sub>3</sub> + Cl<sub>2</sub>, what happens when Cl<sub>2</sub> concentration is increased?
Equilibrium
shifts to the left
View source
What is the role of catalysts in chemical reactions?
Catalysts increase the
reaction rate
View source
Do catalysts change K<sub>c</sub>?
No, K<sub>c</sub> is only
temperature-dependent
View source
How do catalysts affect the time to reach equilibrium?
Catalysts
help reach equilibrium more
rapidly
View source
What are the factors affecting K<sub>c</sub>?
Temperature
Concentration
Catalysts (do not affect K<sub>c</sub>)
View source